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Structural Concrete - Hassoun

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630 Chapter 17 Design of Two-Way Slabs<br />

17.8.2 Total Factored Static Moment<br />

If a simply supported beam carries a uniformly distributed load w K/ft, then the maximum positive<br />

bending moment occurs at midspan and equals M 0 = q u l 2 1 ∕8, where l 1 is the span length. If the beam<br />

is fixed at both ends or continuous with equal negative moments at both ends, then the total moment<br />

M 0 = M p (positive moment at midspan) + M n (negative moment at support) = q u l 2 ∕8 (Fig. 17.10).<br />

1<br />

Now if the beam AB carries the load W from a slab that has a width l 2 perpendicular to l 1 , then<br />

W = q u l 2 , and the total moment is<br />

M 0 = (q ul 2 )l 2 1<br />

8<br />

where q u is the load intensity in K/ft 2 . In this expression, the actual moment occurs when l 1 equals<br />

the clear span between supports A and B. If the clear span is denoted by l n , then<br />

M 0 = q ul 2 ln<br />

2 (ACI Code, Eq. 8.10.3.2) (17.11)<br />

8<br />

The clear span, l n , is measured face to face of supports in the direction in which moments are<br />

considered but not less than 0.65 times the span length from center to center of supports. The face<br />

of the support where the negative moments should be calculated is illustrated in Fig. 17.11. The<br />

length l 2 is measured in a direction perpendicular to l n and equals the direction between center to<br />

center of supports (width of slab). The total moment M 0 calculated in the long direction will be<br />

referred to here as M 0l<br />

and that in the short direction, as M 0s<br />

.<br />

Once the total moment, M 0 , is calculated in one direction, it is divided into a positive moment,<br />

M p , and a negative moment, M n , such that M 0 = M p + M n (Fig. 17.10). Then each moment, M p and<br />

M n , is distributed across the width of the slab between the column and middle strips, as is explained<br />

shortly.<br />

17.8.3 Longitudinal Distribution of Moments in Slabs<br />

In a typical interior panel, the total static moment, M 0 , is divided into two moments, the positive<br />

moment, M p ,atmidspan,equalto0.35M 0 ,andthenegativemoment,M n , at each support, equal<br />

to 0.65M 0 , as shown in Fig. 17.12. These values of moment are based on the assumption that the<br />

interior panel is continuous in both directions, with approximately equal spans and loads, so that<br />

the interior joints have no significant rotation. Moreover, the moment values are approximately the<br />

Figure 17.10<br />

Bending moment in a fixed-end beam.

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