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Structural Concrete - Hassoun

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730 Chapter 19 Introduction to Prestressed <strong>Concrete</strong><br />

Increase the live load now to L 3 = 2733 lb/ft. The stresses due to the live load, L 3 ,are<br />

2.733 ×(24)2<br />

M LL = = 196.8K⋅ ft<br />

8<br />

6(196.8 × 12, 000)<br />

σ L3<br />

= =±2050 psi<br />

12(24) 2<br />

The final stresses at the top and bottom fibers due to the dead load, live load (L 3 ), and the<br />

prestressing force are 1825 psi and 0, respectively (Fig. 19.2). Note that the final stresses are<br />

about the same as those in the previous cases, yet the live load has been increased to 2733 lb/ft.<br />

A tensile stress of 225 psi is developed when the prestressing force is applied on the beam. This<br />

stress is less than the modulus of rupture of concrete, f r = 503 psi; hence, cracks will not develop<br />

in the beam.<br />

5. The maximum live load when the eccentric force P acts at e = 6 in. is determined as follows. In the<br />

previous case, the final compressive stress is equal to 1825 psi, which is less than the allowable<br />

stress of 2050 psi. Therefore, the live load may be increased to L 4 = 3033 lb/ft.<br />

Notes:<br />

3.033 ×(24)2<br />

M LL =<br />

8<br />

6(218.4 × 12, 000)<br />

σ L4<br />

= =±2275 psi<br />

12(24) 2<br />

Final stresses due to the dead load, live load (L 4 ), and the prestressing force are −2050 psi and<br />

± 225 psi (Fig. 19.2). The compressive stress is equal to the allowable stress of 2050 psi, and the<br />

tensile stress is less than the modulus of rupture of concrete of 503 psi. In this case, the uniform<br />

live load of 3033 lb/ft has been calculated as follows: Add the maximum allowable compressive<br />

stress of 2050 psi to the initial tensile stress at the top fibers of 225 psi to get 2275 psi. The moment<br />

that will produce a stress at the top fibers of 2275 psi is equal to<br />

( )<br />

bh<br />

2<br />

M = σ<br />

6<br />

= 2.275<br />

6 (12)(24)2 = 2620.8K⋅ in. = 218.4K⋅ ft<br />

M = W L L2<br />

8<br />

and W L = 8 × 218.4<br />

(24) 2 = 3.033 K∕ft<br />

a. The entire concrete section is active in resisting the external loads.<br />

b. The final tensile stress in the section is less than the modulus of rupture of concrete, which indicates<br />

that a crackless concrete section can be achieved under full load.<br />

c. The allowable load on the beam has been increased appreciably due to the application of the<br />

prestressing force.<br />

d. An increase in the eccentricity of the prestressing force will increase the allowable applied load,<br />

provided that the allowable stresses on the section are not exceeded.<br />

19.1.2 Partial Prestressing<br />

A partially prestressed concrete member can be defined as one in which (1) there have been introduced<br />

internal stresses to counteract part of the stresses resulting from external loadings, (2) tensile<br />

stresses are developed in the concrete under working loads, and (3) nonprestressed reinforcement

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