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Structural Concrete - Hassoun

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15.8 Torsion in Reinforced <strong>Concrete</strong> Members (ACI Code Procedure) 541<br />

closed stirrups, and longitudinal reinforcement, A l , in the form of longitudinal bars. The ACI Code,<br />

Section 22.7.6.1, presented the following expression to compute A t and A l :<br />

1. Closed stirrups A t can be calculated as follows:<br />

where<br />

T n = 2A 0A t f yt cot θ<br />

s<br />

(15.24)<br />

T n = T u<br />

and φ = 0.75<br />

φ<br />

A t = area of one leg of transverse closed stirrups<br />

f yt = yield strength of A t ≤ 60 ksi<br />

s = spacing of stirrups<br />

And A 0 and θ were defined in ACI Section 22.7.6.1. Equation 15.24 can be written as<br />

follows:<br />

A t<br />

s =<br />

T n<br />

2A 0 f yt cot θ<br />

If θ = 45 ∘ , then cot θ = 1.0, and if f yt = 60 ksi, then Eq. 15.25 becomes<br />

A t<br />

s =<br />

(15.25)<br />

T n<br />

120A 0<br />

(15.26)<br />

where T n is in K ⋅ in. Spacing of stirrups, s, should not exceed the smaller of P h /8 or 12 in. For<br />

hollow sections in torsion, the distance measured from the centerline of stirrups to the inside<br />

face of the wall shall not be less than 0.5 A 0 h /P h .<br />

2. The additional longitudinal reinforcement, A l , required for torsion should not be less than the<br />

following:<br />

( ) ( )<br />

At fyt<br />

A l = P<br />

s h cot 2 θ (15.27)<br />

f y<br />

If θ = 45 ∘ and f yt = f y = 60 ksi for both stirrups and longitudinal bars, then Eq. 15.27<br />

becomes<br />

( ) ( )<br />

At At<br />

A l = P<br />

s h = 2 (x<br />

s 1 + y 1 ) (15.28)<br />

where P h is as defined in ACI Section 22.7.6.1. Note that reinforcement required for torsion<br />

should be added to that required for the shear, moment, and axial force that act in combination<br />

with torsion. Other limitations for the longitudinal reinforcement, A l , are as follows:<br />

a. The smallest bar diameter of a longitudinal bar is that of no. 3 or stirrup spacing s/24,<br />

whichever is greater.<br />

b. The longitudinal bars should be distributed around the perimeter of the closed stirrups with<br />

a maximum spacing of 12 in.<br />

c. The longitudinal bars must be inside the stirrups with at least one bar in each corner of<br />

the stirrups. Corner bars are found to be effective in developing torsional strength and in<br />

controlling cracking.<br />

d. Torsional reinforcement should be provided for a distance (b t + d) beyond the point theoretically<br />

required, where b t is the width of that part of the cross section containing the<br />

stirrups resisting torsion.

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