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Structural Concrete - Hassoun

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22.9 Deflections (AASHTO 5.7.3.6) 927<br />

The maximum moment due to DW: future wearing surface (AC overlay)<br />

M DW = w DW_intx(L − x) (0.28)(50)(100 − 50)<br />

= = 350 kip ⋅ ft<br />

2<br />

2<br />

2. Live Load<br />

Maximum moment due to uniform lane load of 0.64 klf:<br />

(0.64 klf)x(L − x) (0.64)(50)(100 − 50)<br />

M uniformLL = = = 800 kip ⋅ ft<br />

2<br />

2<br />

Maximum moment due to design truck of HL-93 without dynamic load allowance<br />

( ) ( )<br />

9<br />

M HL93 = 16 kip<br />

8 L + 24.5ft2<br />

9 24.5<br />

− 17.5 ft = 16 (100) +<br />

L<br />

8 100 − 17.5<br />

= 1523.9 kip⋅ ft<br />

Maximum moment due to design tandem without dynamic load allowance<br />

( ) ( L 3ft2 100<br />

M Tandem = 50 kip − 1ft− = 50<br />

4 L<br />

4 − 1 − 3 )<br />

− 1198.5 kip⋅ ft<br />

100<br />

M truck = Max(M HL93 , M Tandem )=max(1523.9, 1198.5) =1523.9 kip⋅ ft<br />

Therefore, design truck will govern the maximum moment [combination (b) in Fig. 22.8].<br />

Pedestrian Live Load (AASHTO 3.6.1.6)<br />

Pedestrian load of 0.075 klf shall be applied to all sidewalks wider than 2.0 ft with vehicular live load<br />

in vehicle lane.<br />

If no side walk provided, therefore, no pedestrian live load is applied.<br />

The maximum moment due to live load including the effects of dynamic load allowance and<br />

load distribution factor is calculated below:<br />

M LL = DM int {M uniformLL +[(1 + IM)M truck ]} = 0.845[800 +(1 + 0.33)1523.9] =2389.7 kip⋅ ft<br />

FACTORED MOMENTS<br />

Factored Moments<br />

Load Factor Combinations:<br />

Use for girder design-working stress<br />

Strength I<br />

Service I<br />

Service III<br />

1.25(DC) + 1.5 (DW) + 1.75(LL + IM)<br />

1.0[DC + DW + (LL + IM)]; HL 93 only<br />

1.0[DC + DW + 0.8(LL + IM)]; HL 93 only<br />

Strenght I = 1.25(M DC1 + M DC )+1.5(M DW )+1.75(M LL )<br />

= 1.25(2045.6 + 255.6)+1.5(350)+1.75(2389.7) =7583 kip ⋅ ft<br />

Service I = 1.0(M DC1 + M DC2 + M DW + M LL )=1.0(2045.6 + 255.6 + 350 + 2389.7)<br />

= 5041 kip ⋅ ft<br />

Service III = 1.0(M DC1 + M DC2 + M DW + 0.8M LL )<br />

= 1.0[2045.6 + 255.6 + 350 + 0.8(2389.7)] = 4563 kip ⋅ ft

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