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Structural Concrete - Hassoun

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370 Chapter 11 Members in Compression and Bending<br />

ε<br />

ε<br />

ε<br />

Figure 11.9<br />

ε ′ s ≥ ε y .<br />

Strain diagram when compression controls. When ε s<br />

c b<br />

and<br />

11.8 STRENGTH OF COLUMNS FOR COMPRESSION FAILURE<br />

If the compressive applied force, P n , exceeds the balanced force, P b , or the eccentricity, e = M n /P n ,<br />

is less than e b , compression failure is expected. In this case compression controls, and the strain in<br />

the concrete will reach 0.003, whereas the strain in the steel is less than ε y (Fig. 11.9). A large part<br />

of the column will be in compression. The neutral axis moves toward the tension steel, increasing<br />

the compression area, and therefore the distance to the neutral axis c is greater than the balanced<br />

c b (Fig. 11.9).<br />

Because it is difficult to predict compression or tension failure whenever a section is given,<br />

compression failure can be assumed when e < 2d/3, which should be checked later. The nominal<br />

load strength, P n , can be calculated using the principles of statics. The analysis of column sections<br />

for compression failure can be achieved using Eqs. 11.10 and Eqs. 11.11 given earlier and one of<br />

the following solutions.<br />

11.8.1 Trial Solution<br />

This solution can be summarized as follows:<br />

1. Calculate the distance to the neutral axis for a balanced section, c b :<br />

( ) 87dt<br />

c b =<br />

(11.17)<br />

87 + f y<br />

where f y is in ksi.<br />

2. Evaluate P n using equilibrium conditions:<br />

P n = C c + C s − T (11.18)<br />

3. Evaluate P n by taking moments about the tension steel, A s :<br />

(<br />

P n ⋅ e ′ = C c d − a )<br />

+ C<br />

2 s (d − d ′ ) (11.19)

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