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Structural Concrete - Hassoun

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762 Chapter 19 Introduction to Prestressed <strong>Concrete</strong><br />

3. For flanged sections, the steel area required to develop the strength of the web (A pw )isused<br />

to check the reinforcement index.<br />

( ) fps<br />

ω pw (web) =ρ pw ≤ 0.32β 1<br />

where<br />

ρ pw = A pw<br />

b w d d<br />

If nonprestressed reinforcement is used, then the reinforcement limitations are<br />

where<br />

ω pw +<br />

ω w = A s<br />

b w d<br />

f ′ c<br />

d<br />

d pw<br />

(ω w − ω ′ w) ≤ 0.32β 1<br />

( fy<br />

f ′ c<br />

)<br />

ω ′ w = A′ s<br />

b w d<br />

When compression steel A ′ s is not used, then ω ′ w = 0. The preceding reinforcement conditions<br />

must be met in the analysis and design of partially prestressed concrete members.<br />

For class C of prestressed concrete flexural members, where f t > 12 √ f c ′ (cracked section),<br />

crack control provisions should be used as explained in Section 6.7 of this textbook. When<br />

using Eq. 6.18 for the maximum spacing s, the ACI Code, Section 24.3.2, specifies the following:<br />

a. For tendons, use 2 of the spacing s.<br />

3<br />

b. For a combination of nonprestressed reinforcement and tendons, use 5 of the spacing s.<br />

6<br />

c. For tendons, use Δf ps in place of f s ,whereΔf ps is the difference between the stress computed<br />

in the prestressing tendons at service load based on a cracked section and the decompression<br />

stress, f dc , in the prestressing tendons, which may be taken conservatively, to be equal<br />

to the effective prestress, f se . Note that Δf ps should not exceed 36 ksi. If it is less than or<br />

equal to 20 ksi, the spacing requirement will not apply. Equation 6.17 can be written as<br />

follows:<br />

( ) [ ( ) ]<br />

2 40<br />

s = 15 − 2.5C<br />

3 Δ f c<br />

ps<br />

( fy<br />

f ′ c<br />

)<br />

19.6 CRACKING MOMENT<br />

Cracks may develop in a prestressed concrete beam when the tensile stress at the extreme fibers<br />

of the critical section equals or exceeds the modulus of rupture of concrete, f r . The value of f r<br />

for normal-weight concrete may be assumed to be equal to 7.5λ √ f ′ c where λ = 1.0. The stress at<br />

the bottom fibers of a simply supported beam produced by the prestressing force and the cracking<br />

moment is<br />

σ b =− F A − (Fe)y b<br />

I<br />

+ M cry b<br />

I<br />

When σ b = f r = 7.5λ √ f c, ′ then the cracking moment is<br />

M cr = I<br />

(<br />

7.5λ √ f c ′ + F y b A + (Fe) y )<br />

b<br />

I<br />

(19.48)

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