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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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Section 15.1 Double Integrals over Rectangles 997

Average Value

Recall from Section 6.5 that the average value of a function f of one variable defined on

an interval fa, bg is

f ave − 1

b 2 a yb f sxd dx

a

In a similar fashion we define the average value of a function f of two variables defined

on a rectangle R to be

f ave − 1

yy f sx, yd dA

AsRd

R

where AsRd is the area of R.

If f sx, yd > 0, the equation

AsRd 3 f ave − yy f sx, yd dA

R

FIGURE 17

says that the box with base R and height f ave has the same volume as the solid that lies

under the graph of f. [If z − f sx, yd describes a mountainous region and you chop off the

tops of the mountains at height f ave , then you can use them to fill in the valleys so that the

region becomes completely flat. See Figure 17.]

Example 9 The contour map in Figure 18 shows the snowfall, in inches, that fell on the

state of Colorado on December 20 and 21, 2006. (The state is in the shape of a rectangle

that measures 388 mi west to east and 276 mi south to north.) Use the contour map to

estimate the average snowfall for the entire state of Colorado on those days.

40 36

44 32

28

24

12

16

20

16

12

40

36

32

12

28

24

0 4 8 12 16

32

28

24

20

8

FIGURE 18

SOLUTIon Let’s place the origin at the southwest corner of the state. Then 0 < x < 388,

0 < y < 276, and f sx, yd is the snowfall, in inches, at a location x miles to the east and

y miles to the north of the origin. If R is the rectangle that represents Colorado, then the

average snowfall for the state on December 20–21 was

f ave − 1

y y f sx, yd dA

AsRd

R

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Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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