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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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Section 3.6 Derivatives of Logarithmic Functions 221

If we hadn’t used logarithmic differentiation

in Example 7, we would have

had to use both the Quotient Rule

and the Product Rule. The resulting

calculation would have been

horrendous.

Because we have an explicit expression for y, we can substitute and write

dy

dx − x 3y4 sx 2 1 1S 3

s3x 1 2d 5 4x 1 x

x 2 1 1 2 15

3x 1 2D

Steps in Logarithmic Differentiation

1. Take natural logarithms of both sides of an equation y − f sxd and use the Laws

of Logarithms to simplify.

2. Differentiate implicitly with respect to x.

3. Solve the resulting equation for y9.

If f sxd , 0 for some values of x, then ln f sxd is not defined, but we can write

| y | − | f sxd | and use Equation 4. We illustrate this procedure by proving the general

version of the Power Rule, as promised in Section 3.1.

The Power Rule If n is any real number and f sxd − x n , then

f 9sxd − nx n21

If x − 0, we can show that f 9s0d − 0

for n . 1 directly from the definition

of a derivative.

Proof Let y − x n and use logarithmic differentiation:

Therefore

ln | y | − ln | x | n − n ln | x | x ± 0

y9

y − n x

Hence

y9 − n y x − n x n

x

− nx

n21

Constant base, constant exponent

Variable base, constant exponent

Constant base, variable exponent

Variable base, variable exponent

You should distinguish carefully between the Power Rule fsx n d9 − nx n21 g, where the

base is variable and the exponent is constant, and the rule for differentiating exponential

functions fsb x d9 − b x ln bg, where the base is constant and the exponent is variable.

In general there are four cases for exponents and bases:

d

1.

dx sb n d − 0 (b and n are constants)

d

2.

dx f f sxdgn − nf f sxdg n21 f 9sxd

d

3.

dx fb tsxd g − b tsxd sln bdt9sxd

4. To find sdydxdf f sxdg tsxd , logaritmic differentiation can be used, as in the next

example.

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