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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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1046 Chapter 15 Multiple Integrals

z

Q

The relationship between rectangular and spherical coordinates can be seen from Figure

5. From triangles OPQ and OPP9 we have

z

˙

˙

P(x, y, z)

P(∏, ¨, ˙)

z − cos

r − sin

But x − r cos and y − r sin , so to convert from spherical to rectangular coordinates,

we use the equations

x

O

¨

r

y

1 x − sin cos y − sin sin z − cos

x

y

Pª(x, y, 0)

Also, the distance formula shows that

FIGURE 5

2 2 − x 2 1 y 2 1 z 2

We use this equation in converting from rectangular to spherical coordinates.

ExamplE 1 The point s2, y4, y3d is given in spherical coordinates. Plot the point

and find its rectangular coordinates.

z

SOLUtion We plot the point in Figure 6. From Equations 1 we have

x

0

π

4

π

3

2

(2, π/4, π/3)

y

x − sin cos − 2 sin 3 cos 4 − 2 S s3

2

DS 1

s2

D −Î 3 2

y − sin sin − 2 sin 3 sin 4 − 2 S s3

2

DS 1

s2

D −Î 3 2

FIGURE 6

z − cos − 2 cos 3 − 2( 1 2) − 1

Thus the point s2, y4, y3d is ss3y2 , s3y2 , 1d in rectangular coordinates.

Warning There is not universal

agreement on the notation for spherical

coordinates. Most books on physics

reverse the meanings of and and use

r in place of .

ExamplE 2 The point s0, 2s3 , 22d is given in rectangular coordinates. Find spherical

coordinates for this point.

SOLUtion From Equation 2 we have

and so Equations 1 give

− sx 2 1 y 2 1 z 2 − s0 1 12 1 4 − 4

cos − z − 22

4 − 2 1 2

− 2 3

tec In Module 15.8 you can investigate

families of surfaces in cylindrical

and spherical coordinates.

cos −

x

sin − 0 − 2

(Note that ± 3y2 because y − 2s3 . 0.) Therefore spherical coordinates of the

given point are s4, y2, 2y3d.

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