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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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Chapter 14

Concept Check Answers (continued)

8. Define the linearization of f at sa, bd. What is the corresponding

linear approximation? What is the geometric interpretation

of the linear approximation?

The linearization of f at sa, bd is the linear function whose

graph is the tangent plane to the surface z − f sx, yd at the

point sa, b, f sa, bdd:

Lsx, yd − f sa, bd 1 f xsa, bdsx 2 ad 1 f ysa, bdsy 2 bd

The linear approximation of f at sa, bd is

f sx, yd < f sa, bd 1 f xsa, bdsx 2 ad 1 f ysa, bdsy 2 bd

Geometrically, the linear approximation says that function

values f sx, yd can be approximated by values Lsx, yd from the

tangent plane to the graph of f at sa, b, f sa, bdd when sx, yd is

near sa, bd.

9. (a) What does it mean to say that f is differentiable at sa, bd?

If z − f sx, yd, then f is differentiable at sa, bd if Dz can be

expressed in the form

Dz − f xsa, bd Dx 1 f ysa, bd Dy 1 « 1 Dx 1 « 2 Dy

where « 1 and « 2 l 0 as sDx, Dyd l s0, 0d. In other

words, a differentiable function is one for which the linear

approximation as stated above is a good approximation

when sx, yd is near sa, bd.

(b) How do you usually verify that f is differentiable?

If the partial derivatives f x and f y exist near sa, bd and are

continuous at sa, bd, then f is differentiable at sa, bd.

10. If z − f sx, yd, what are the differentials dx, dy, and dz?

The differentials dx and dy are independent variables that

can be given any values. If f is differentiable, the differential

dz is then defined by

dz − f xsx, yd dx 1 f ysx, yd dy

11. State the Chain Rule for the case where z − f sx, yd and x and

y are functions of one variable. What if x and y are functions

of two variables?

Suppose that z − f sx, yd is a differentiable function of x and

y, where x − tstd and y − hstd are both differentiable functions

of t. Then z is a differentiable function of t and

dz

dt − −f

−x

dx

dt 1 −f

−y

If z − f sx, yd is a differentiable function of x and y, where

x − tss, td and y − hss, td are differentiable functions of s and

t, then

−z

−s − −z

−x

−x

−s 1 −z

−y

−y

−s

dy

dt

−z

−t − −z

−x

−x

−t 1 −z

−y

−y

−t

12. If z is defined implicitly as a function of x and y by an equation

of the form Fsx, y, zd − 0, how do you find −zy−x and

−zy−y?

If F is differentiable and −Fy−z ± 0, then

−z

−x − 2

−F

−x

−F

−z

−z

−y − 2

−F

−y

−F

−z

13. (a) Write an expression as a limit for the directional derivative

of f at sx 0, y 0d in the direction of a unit vector

u − k a, b l. How do you interpret it as a rate? How do

you interpret it geometrically?

The directional derivative of f at sx 0, y 0d in the direction

of u is

D u f sx 0, y 0d − lim

h l 0

if this limit exists.

f sx 0 1 ha, y 0 1 hbd 2 f sx 0, y 0d

h

We can interpret it as the rate of change of f (with respect

to distance) at sx 0, y 0d in the direction of u.

Geometrically, if P is the point sx 0, y 0, f sx 0, y 0dd on the

graph of f and C is the curve of intersection of the graph

of f with the vertical plane that passes through P in the

direction of u, then D u f sx 0, y 0d is the slope of the tangent

line to C at P.

(b) If f is differentiable, write an expression for D u f sx 0, y 0d

in terms of f x and f y.

D u f sx 0, y 0d − f xsx 0, y 0d a 1 f ysx 0, y 0d b

14. (a) Define the gradient vector =f for a function f of two or

three variables.

If f is a function of two variables, then

=f sx, yd − k f xsx, yd, f ysx, yd l − −f

−x i 1 −f

−y j

For a function f of three variables,

=f sx, y, zd − k f xsx, y, zd, f ysx, y, zd, f zsx, y, zd l

− −f

−x i 1 −f

−y j 1 −f

−z k

(b) Express D u f in terms of =f .

or

D u f sx, yd − =f sx, yd u

D u f sx, y, zd − =f sx, y, zd u

(continued)

Copyright 2016 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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