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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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392 Chapter 5 Integrals

of x at which tsxd starts to decrease. [Unlike the integral in Problem 2, it is impossible

to evaluate the integral defining t to obtain an explicit expression for tsxd.]

(c) Use the integration command on your calculator or computer to estimate ts0.2d,

ts0.4d, ts0.6d, . . . , ts1.8d, ts2d. Then use these values to sketch a graph of t.

(d) Use your graph of t from part (c) to sketch the graph of t9 using the interpretation of

t9sxd as the slope of a tangent line. How does the graph of t9 compare with the graph

of f ?

4. Suppose f is a continuous function on the interval fa, bg and we define a new function t

by the equation

tsxd − y x

f std dt

a

Based on your results in Problems 1–3, conjecture an expression for t9sxd.

y

y=f(t)

The Fundamental Theorem of Calculus is appropriately named because it establishes a

con nection between the two branches of calculus: differential calculus and integral

calculus. Differential calculus arose from the tangent problem, whereas integral calculus

arose from a seemingly unrelated problem, the area problem. Newton’s mentor at

Cambridge, Isaac Barrow (1630 –1677), discovered that these two problems are actually

closely related. In fact, he realized that differentiation and integration are inverse

processes. The Fundamental Theorem of Calculus gives the precise inverse relationship

between the derivative and the integral. It was Newton and Leibniz who exploited this

relationship and used it to develop calculus into a systematic mathema tical method. In

particular, they saw that the Fundamental Theorem enabled them to compute areas and

integrals very easily without having to compute them as limits of sums as we did in Sections

5.1 and 5.2.

The first part of the Fundamental Theorem deals with functions defined by an equation

of the form

area=©

1

tsxd − y x

f std dt

a

0 a

x

FIGURE 1

y

2

y=f(t)

1

0 1 2 4

b

t

t

where f is a continuous function on fa, bg and x varies between a and b. Observe that t

depends only on x, which appears as the variable upper limit in the integral. If x is a fixed

number, then the integral y x a

f std dt is a definite number. If we then let x vary, the number

y x a

f std dt also varies and defines a function of x denoted by tsxd.

If f happens to be a positive function, then tsxd can be interpreted as the area under the

graph of f from a to x, where x can vary from a to b. (Think of t as the “area so far”

function; see Figure 1.)

Example 1 If f is the function whose graph is shown in Figure 2 and

tsxd − y x 0

f std dt, find the values of ts0d, ts1d, ts2d, ts3d, ts4d, and ts5d. Then sketch a

rough graph of t.

FIGURE 2

SOLUTION First we notice that ts0d − y 0 0

f std dt − 0. From Figure 3 we see that ts1d is

the area of a triangle:

ts1d − y 1

f std dt − 1 2 s1 ? 2d − 1

0

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