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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

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A104 Appendix I Answers to Odd-Numbered Exercises

43. (a) Cstd − sC 0 2 rykde 2kt 1 ryk (b) ryk; the concentration

approaches ryk regardless of the value of C 0

45. (a) 15e 2ty100 kg (b) 15e 20.2 < 12.3 kg

47. About 4.9% 49. tyk

51. (a) L 1 − KL2 k (b) B − KV 0.0794

53. (a) dAydt − ksA sM 2 Ad (b) Astd − MS Ce sM kt 2

2 1

,

Ce sM kt 1 1D

sM 1 sA0

where C − and A 0 − As0d

sM 2 sA 0

Exercises 9.4 • page 617

1200

1. (a) 1200; 0.04 (b) Pstd −

20.04t

(c) 87

1 1 19e

3. (a) 100; 0.05 (b) Where P is close to 0 or 100;

on the line P − 50; 0 , P 0 , 100; P 0 . 100

(c)

P

150

P¸=140

P¸=120

100

P¸=80

P¸=60

50

P¸=40

P¸=20

0 20 40 60 t

Solutions approach 100; some increase and some decrease, some

have an inflection point but others don’t; solutions with P 0 − 20

and P 0 − 40 have inflection points at P − 50

(d) P − 0, P − 100; other solutions move away from P − 0 and

toward P − 100

5. (a) 3.23 3 10 7 kg (b) <1.55 years 7. 9000

9. (a) dP − 1

dt 305 P S1 2

20D

P

(b) 6.24 billion (c) 7.57 billion; 13.87 billion

y 0

11. (a) dyydt − kys1 2 yd (b) y −

y 0 1 s1 2 y 0de 2kt

(c) 3:36 PM

15. P Estd − 1909.7761s1.0796d t 1 94,000;

33,086.4394

P Lstd −

1 94,000

1 1 12.3428e 20.1657t

130,000

(d)

P

1200

800

400

0 40 80 120 t

ty25

250 2 750ke

(e) Pstd −

1 2 ke ty25

where k − 1 11 , 2 1 9

21. (b)

P

1400

1200

1000

800

600

400

200

P 1200

0 20 40 60 80 100 t

0 , P 0 , 250: P l 0;

P 0 − 250: P l 250;

P 0 . 250: P l 750

0 120

t

0 , P 0 , 200: P l 0;

P 0 − 200: P l 200;

P 0 . 200: P l 1000

sM2mdskyMdt

msM 2 P0d 1 MsP0 2 mde

(c) Pstd −

M 2 P 0 1 sP 0 2 mde sM2mdskyMdt

23. (a) Pstd − P 0e skyrdfsinsrt 2 d 1 sin g (b) Does not exist

Exercises 9.5 • page 625

1. No 3. Yes 5. y − 1 1 Ce 2x

7. y − x 2 1 1 Ce 2x 9. y − 2 3 sx 1 Cyx

11. y − x 2 sln x 1 Cd 13. y − 1 3 t23 s1 1 t 2 d 3y2 1 Ct 23

15. y − 1 x ln x 2 1 x 1 3 x 2 17. u − 2t 2 1 t 3

19. y − 2x cos x 2 x

21. y − sx 2 1de x 1 C

x 2

C=3

C=5

C=7

5

C=3

C=5

C=7

P

P L

P E

t (in years)

_3

C=1

3

90,000

1960

2010

17. (a) Pstd − m k 1 SP 0 2 m kDe kt (b) m , kP 0

(c) m − kP 0, m . kP 0 (d) Declining

19. (a) Fish are caught at a rate of 15 per week.

(b) See part (d). (c) P − 250, P − 750

25. y − 6SCx 4 1

5xD

2 21y2

C=_5

C=_3

C=_1

_5

C=_5

C=_3

C=_1

6et Ans. 9.5.21

12.07.06

27. (a) Istd − 4 2 4e 25t (b) 4 2 4e 21y2 < 1.57 A

29. Qstd − 3s1 2 e 24t d, Istd − 12e 24t

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