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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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Section 15.4 Applications of Double Integrals 1023

find the probability that a moviegoer waits a total of less than 20 minutes before taking

his or her seat.

SOLUTION Assuming that both the waiting time X for the ticket purchase and the

waiting time Y in the refreshment line are modeled by exponential probability density

functions, we can write the individual density functions as

f 1 sxd −H 0 if x , 0

1

10 e2xy10 if x > 0

f 2 syd −H 0 if y , 0

1

5 e2yy5 if y > 0

Since X and Y are independent, the joint density function is the product:

1

50

f sx, yd − f 1 sxd f 2 syd −H

e2xy10 e 2yy5

0

if x > 0, y > 0

otherwise

We are asked for the probability that X 1 Y , 20:

PsX 1 Y , 20d − PssX, Yd [ Dd

y

20

D

x+y=20

where D is the triangular region shown in Figure 8. Thus

PsX 1 Y , 20d − y f sx, yd dA − y 20

y 202x 1

50

0 0

e2xy10 e 2yy5 dy dx

D

− 1

50 y 20

fe 2xy10 s25de 2yy5 y−202x

g y−0 dx

0

0

20

x

− 1

10 y 20

e 2xy10 s1 2 e sx220dy5 d dx

0

FIGURE 8

− 1

10 y 20

se 2xy10 2 e 24 e xy10 d dx

0

− 1 1 e 24 2 2e 22 < 0.7476

This means that about 75% of the moviegoers wait less than 20 minutes before taking

their seats.

Expected Values

Recall from Section 8.5 that if X is a random variable with probability density function

f, then its mean is

− y`

x f sxd dx

2`

Now if X and Y are random variables with joint density function f, we define the X-mean

and Y-mean, also called the expected values of X and Y, to be

11 1 − y x f sx, yd dA

R 2

2 − y y f sx, yd dA

R 2

Notice how closely the expressions for 1 and 2 in (11) resemble the moments M x and

M y of a lamina with density function in Equations 3 and 4. In fact, we can think of

probability as being like continuously distributed mass. We calculate probability the way

we calculate mass—by integrating a density function. And because the total “probability

mass” is 1, the expressions for x and y in (5) show that we can think of the expected values

of X and Y, 1 and 2 , as the coordinates of the “center of mass” of the probability

distribution.

Copyright 2016 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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