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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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876 Chapter 13 Vector Functions

Kepler’s Laws

1. A planet revolves around the sun in an elliptical orbit with the sun at one focus.

2. The line joining the sun to a planet sweeps out equal areas in equal times.

3. The square of the period of revolution of a planet is proportional to the cube of

the length of the major axis of its orbit.

In his book Principia Mathematica of 1687, Sir Isaac Newton was able to show that

these three laws are consequences of two of his own laws, the Second Law of Motion and

the Law of Universal Gravitation. In what follows we prove Kepler’s First Law. The

remaining laws are left as exercises (with hints).

Since the gravitational force of the sun on a planet is so much larger than the forces

exerted by other celestial bodies, we can safely ignore all bodies in the universe except the

sun and one planet revolving about it. We use a coordinate system with the sun at the

ori gin and we let r − rstd be the position vector of the planet. (Equally well, r could be

the position vector of the moon or a satellite moving around the earth or a comet moving

around a star.) The velocity vector is v − r9 and the acceleration vector is a − r0. We use

the following laws of Newton:

Second Law of Motion: F − ma

Law of Gravitation: F − 2 GMm

r 3 r − 2 GMm

r 2 u

where F is the gravitational force on the planet, m and M are the masses of the planet and

the sun, G is the gravitational constant, r − | r | , and u − s1yrdr is the unit vector in the

direction of r.

We first show that the planet moves in one plane. By equating the expressions for F in

Newton’s two laws, we find that

a − 2 GM

r r 3

and so a is parallel to r. It follows that r 3 a − 0. We use Formula 5 in Theorem 13.2.3 to

write

d

sr 3 vd − r9 3 v 1 r 3 v9

dt

− v 3 v 1 r 3 a − 0 1 0 − 0

Therefore

r 3 v − h

where h is a constant vector. (We may assume that h ± 0; that is, r and v are not parallel.)

This means that the vector r − rstd is perpendicular to h for all values of t, so the

planet always lies in the plane through the origin perpendicular to h. Thus the orbit of the

planet is a plane curve.

To prove Kepler’s First Law we rewrite the vector h as follows:

h − r 3 v − r 3 r9 − r u 3 sr ud9

− r u 3 sr u9 1 r9ud − r 2 su 3 u9d 1 rr9su 3 ud

− r 2 su 3 u9d

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