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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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Section 4.6 Graphing with Calculus and Calculators 327

π

The family of functions

f sxd − sinsx 1 sin cxd

where c is a constant, occurs in applications

to frequency modulation (FM)

synthesis. A sine wave is modulated by

a wave with a different frequency

ssin cxd. The case where c − 2 is

studied in Example 4. Exercise 27

explores another special case.

1.2

0

_1.2

FIGURE 16

1.2

y=ƒ

y=fª(x)

0 π

_1.2

FIGURE 17

1.2

f

π

this and locate them more accurately, we calculate that

f 9sxd − cossx 1 sin 2xd ? s1 1 2 cos 2xd

and graph both f and f 9 in Figure 16.

Using zoom-in and the First Derivative Test, we find the following approximate

values:

The second derivative is

Intervals of increase: s0, 0.6d, s1.0, 1.6d, s2.1, 2.5d

Intervals of decrease: s0.6, 1.0d, s1.6, 2.1d, s2.5, d

Local maximum values: f s0.6d < 1, f s1.6d < 1, f s2.5d < 1

Local minimum values: f s1.0d < 0.94, f s2.1d < 0.94

f 0sxd − 2s1 1 2 cos 2xd 2 sinsx 1 sin 2xd 2 4 sin 2x cossx 1 sin 2xd

Graphing both f and f 0 in Figure 17, we obtain the following approximate values:

Concave upward on: s0.8, 1.3d, s1.8, 2.3d

Concave downward on: s0, 0.8d, s1.3, 1.8d, s2.3, d

Inflection points: s0, 0d, s0.8, 0.97d, s1.3, 0.97d, s1.8, 0.97d, s2.3, 0.97d

Having checked that Figure 15 does indeed represent f accurately for 0 < x < ,

we can state that the extended graph in Figure 18 represents f accurately for

22 < x < 2.

Our final example is concerned with families of functions. This means that the functions

in the family are related to each other by a formula that contains one or more arbitrary

constants. Each value of the constant gives rise to a member of the family and the

idea is to see how the graph of the function changes as the constant changes.

n

_2π

ExamplE 5 How does the graph of f sxd − 1ysx 2 1 2x 1 cd vary as c varies?

_1.2

SOLUTION The graphs in Figures 19 and 20 (the special cases c − 2 and c − 22)

show two very different-looking curves.

FIGURE 18

2

2

y= 1

≈+2x-2

_5 4

1

y=

≈+2x+2

_5 4

_2

FIGURE 19

FIGURE 20

c − 2 c − 22

_2

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