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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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914 Chapter 14 Partial Derivatives

4 If f is a function of two variables, its partial derivatives are the functions f x

and f y defined by

f x sx, yd − lim

h l 0

f y sx, yd − lim

h l 0

f sx 1 h, yd 2 f sx, yd

h

f sx, y 1 hd 2 f sx, yd

h

There are many alternative notations for partial derivatives. For instance, instead of

f x we can write f 1 or D 1 f (to indicate differentiation with respect to the first variable) or

−fy−x. But here −fy−x can’t be interpreted as a ratio of differentials.

Notations for Partial Derivatives If z − f sx, yd, we write

f x sx, yd − f x − −f

−x − − −z

f sx, yd −

−x −x − f 1 − D 1 f − D x f

f y sx, yd − f y − −f

−y − − −z

f sx, yd −

−y −y − f 2 − D 2 f − D y f

To compute partial derivatives, all we have to do is remember from Equation 1 that

the partial derivative with respect to x is just the ordinary derivative of the function t of

a single variable that we get by keeping y fixed. Thus we have the following rule.

Rule for Finding Partial Derivatives of z − f sx, yd

1. To find f x , regard y as a constant and differentiate f sx, yd with respect to x.

2. To find f y , regard x as a constant and differentiate f sx, yd with respect to y.

EXAMPLE 1 If f sx, yd − x 3 1 x 2 y 3 2 2y 2 , find f x s2, 1d and f y s2, 1d.

SOLUTION Holding y constant and differentiating with respect to x, we get

f x sx, yd − 3x 2 1 2xy 3

and so

f x s2, 1d − 3 ? 2 2 1 2 ? 2 ? 1 3 − 16

Holding x constant and differentiating with respect to y, we get

f y sx, yd − 3x 2 y 2 2 4y

f y s2, 1d − 3 ? 2 2 ? 1 2 2 4 ? 1 − 8

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