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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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Section 12.4 The Cross Product 817

a rotation (through an angle less than 180°) from a to b, then your thumb points in the

direction of a 3 b.

Now that we know the direction of the vector a 3 b, the remaining thing we need to

complete its geometric description is its length | a 3 b | . This is given by the following

theorem.

9 Theorem If is the angle between a and b (so 0 < < ), then

| a 3 b | − | a | | b | sin

TEC Visual 12.4 shows how a 3 b

changes as b changes.

Proof From the definitions of the cross product and length of a vector, we have

| a 3 b | 2 − sa 2 b 3 2 a 3 b 2 d 2 1 sa 3 b 1 2 a 1 b 3 d 2 1 sa 1 b 2 2 a 2 b 1 d 2

− a 2 2 b 2 3 2 2a 2 a 3 b 2 b 3 1 a 2 3 b 2 2 1 a 2 3 b 2 1 2 2a 1 a 3 b 1 b 3 1 a 2 1 b 2 3

1 a 2 1 b 2 2 2 2a 1 a 2 b 1 b 2 1 a 2 2 b 2 1

− sa 2 1 1 a 2 2 1 a 2 3dsb 2 1 1 b 2 2 1 b 2 3 d 2 sa 1 b 1 1 a 2 b 2 1 a 3 b 3 d 2

− | a | 2 | b | 2 2 sa ? bd 2

− | a | 2 | b | 2 2 | a | 2 | b | 2 cos 2 (by Theorem 12.3.3)

− | a | 2 | b | 2 s1 2 cos 2 d

− | a | 2 | b | 2 sin 2

Taking square roots and observing that ssin 2 − sin because sin > 0 when

0 < < , we have

| a 3 b | − | a | | b | sin ■

Geometric characterization of a 3 b

Since a vector is completely determined by its magnitude and direction, we can now

say that a 3 b is the vector that is perpendicular to both a and b, whose orientation is

determined by the right-hand rule, and whose length is | a | | b | sin . In fact, that is

exactly how physicists define a 3 b.

10 Corollary Two nonzero vectors a and b are parallel if and only if

a 3 b − 0

Proof Two nonzero vectors a and b are parallel if and only if − 0 or . In either

case sin − 0, so | a 3 b | − 0 and therefore a 3 b − 0.

b b sin ¨

¨

a

FIGURE 2

The geometric interpretation of Theorem 9 can be seen by looking at Figure 2. If a

and b are represented by directed line segments with the same initial point, then they

determine a parallelogram with base | a | , altitude | b | sin , and area

A − | a | (| b | sin ) − | a 3 b |

Thus we have the following way of interpreting the magnitude of a cross product.

Copyright 2016 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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