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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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Section 14.1 Functions of Several Variables 891

x

(2, 0, 0)

FIGURE 66

z

(0, 0, 6)

(0, 3, 0)

y

Example 5 Sketch the graph of the function f sx, yd − 6 2 3x 2 2y.

SOLUTION The graph of f has the equation z − 6 2 3x 2 2y, or 3x 1 2y 1 z − 6,

which represents a plane. To graph the plane we first find the intercepts. Putting

y − z − 0 in the equation, we get x − 2 as the x-intercept. Similarly, the y-intercept

is 3 and the z-intercept is 6. This helps us sketch the portion of the graph that lies in the

first octant in Figure 6.

The function in Example 5 is a special case of the function

f sx, yd − ax 1 by 1 c

which is called a linear function. The graph of such a function has the equation

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04/23/10

MasterID: 01531

z − ax 1 by 1 c or ax 1 by 2 z 1 c − 0

so it is a plane. In much the same way that linear functions of one variable are important

in single-variable calculus, we will see that linear functions of two variables play a central

role in multivariable calculus.

Example 6 Sketch the graph of tsx, yd − s9 2 x 2 2 y 2 .

0

(0, 0, 3)

(0 , 3, 0)

(3, 0, 0) y

x

z

FIGURE 77

Graph of tsx, g(x, ydy )= −œ„„„„„„„„„

s9 9-≈-¥ 2 x 2 2 y 2

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SOLUTION The graph has equation z − s9 2 x 2 2 y 2 . We square both sides of this

equation to obtain z 2 − 9 2 x 2 2 y 2 , or x 2 1 y 2 1 z 2 − 9, which we recognize as an

equation of the sphere with center the origin and radius 3. But, since z > 0, the graph

of t is just the top half of this sphere (see Figure 7).

Note An entire sphere can’t be represented by a single function of x and y. As we

saw in Example 6, the upper hemisphere of the sphere x 2 1 y 2 1 z 2 − 9 is represented

by the function tsx, yd − s9 2 x 2 2 y 2 . The lower hemisphere is represented by the

function hsx, yd − 2s9 2 x 2 2 y 2 .

Example 7 Use a computer to draw the graph of the Cobb-Douglas production

function PsL, Kd − 1.01L 0.75 K 0.25 .

SOLUTION Figure 8 shows the graph of P for values of the labor L and capital K that

lie between 0 and 300. The computer has drawn the surface by plotting vertical traces.

We see from these traces that the value of the production P increases as either L or K

increases, as is to be expected.

300

200

P

100

FIGURE 88

0

300

200

K

100

0

0 100

200

L

300

Example 8 Find the domain and range and sketch the graph of hsx, yd − 4x 2 1 y 2 .

SOLUTION Notice that hsx, yd is defined for all possible ordered pairs of real numbers

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sx, yd, so the domain is R 2 , the entire xy-plane. The range of h is the set f0, `d of all

nonnegative 04/23/10 real numbers. [Notice that x 2 > 0 and y 2 > 0, so hsx, yd > 0 for all x

MasterID: 01533

Copyright 2016 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

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