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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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610 Chapter 9 Differential Equations

;

3. Let t 1 be the time that the ball takes to reach its maximum height. Show that

t 1 − S m p

ln mt 1 pv0D

mt

Find this time for a ball with mass 1 kg and initial velocity 20 mys. Assume the air resistance

is 1 10 of the speed.

4. Let t 2 be the time at which the ball falls back to earth. For the particular ball in Prob lem 3,

estimate t 2 by using a graph of the height function ystd. Which is faster, going up or coming

down?

5. In general, it’s not easy to find t 2 because it’s impossible to solve the equation ystd − 0

explicitly. We can, however, use an indirect method to determine whether ascent or descent is

faster: we determine whether ys2t 1d is positive or negative. Show that

ys2t 1d − m 2 t

Sx 2 D

1 p 2 x 2 2 ln x

where x − e pt 1ym

. Then show that x . 1 and the function

f sxd − x 2 1 x 2 2 ln x

is increasing for x . 1. Use this result to decide whether ys2t 1d is positive or negative.

What can you conclude? Is ascent or descent faster?

In this section we investigate differential equations that are used to model population

growth: the law of natural growth, the logistic equation, and several others.

The Law of Natural Growth

One of the models for population growth that we considered in Section 9.1 was based

on the assumption that the population grows at a rate proportional to the size of the

population:

dP

− kP

dt

Is that a reasonable assumption? Suppose we have a population (of bacteria, for instance)

with size P − 1000 and at a certain time it is growing at a rate of P9 − 300 bacteria per

hour. Now let’s take another 1000 bacteria of the same type and put them with the first

pop ulation. Each half of the combined population was previously growing at a rate of

300 bac teria per hour. We would expect the total population of 2000 to increase at a rate

of 600 bacteria per hour initially (provided there’s enough room and nutrition). So if

we double the size, we double the growth rate. It seems reasonable that the growth rate

should be proportional to the size.

In general, if Pstd is the value of a quantity y at time t and if the rate of change of P

with respect to t is proportional to its size Pstd at any time, then

1

dP

dt

− kP

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