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James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

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948 Chapter 14 Partial Derivatives

EXAMPLE 1 Use the weather map in Figure 1 to estimate the value of the directional

derivative of the temperature function at Reno in the southeasterly direction.

SOLUTION The unit vector directed toward the southeast is u − si 2 jdys2 , but we

won’t need to use this expression. We start by drawing a line through Reno toward the

southeast (see Figure 4).

60

50

Reno

San

Francisco

60

70

70

Las

Vegas

80

FIGURE 4

0 50 100 150 200

(Distance in miles)

Los Angeles

7et140604 We approximate the directional derivative D u T by the average rate of change of the

temperature 05/04/10between the points where this line intersects the isothermals T − 50 and

TMasterID: − 60. The temperature 01604 at the point southeast of Reno is T − 608F and the temperature

at the point northwest of Reno is T − 508F. The distance between these points

looks to be about 75 miles. So the rate of change of the temperature in the southeasterly

direction is

D u T <

60 2 50

75

− 10

75 < 0.138Fymi ■

When we compute the directional derivative of a function defined by a formula, we

generally use the following theorem.

3 Theorem If f is a differentiable function of x and y, then f has a directional

derivative in the direction of any unit vector u − ka, bl and

D u f sx, yd − f x sx, yd a 1 f y sx, yd b

Proof If we define a function t of the single variable h by

tshd − f sx 0 1 ha, y 0 1 hbd

then, by the definition of a derivative, we have

tshd 2 ts0d

4 t9s0d − lim

− lim

h l 0 h

h l 0

f sx 0 1 ha, y 0 1 hbd 2 f sx 0 , y 0 d

h

− D u f sx 0 , y 0 d

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