10.06.2022 Views

James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

A five star textbook for college calculus

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

288 Chapter 4 Applications of Differentiation

Figure 2 shows a graph of the function

f sxd − x 3 1 x 2 1 discussed in

Example 2. Rolle’s Theorem shows

that, no matter how much we enlarge

the viewing rectangle, we can never

find a second x-intercept.

3

polynomial, it is continuous, so the Intermediate Value Theorem states that there is a

number c between 0 and 1 such that f scd − 0. Thus the given equation has a root.

To show that the equation has no other real root, we use Rolle’s Theorem and argue

by contradiction. Suppose that it had two roots a and b. Then f sad − 0 − f sbd and,

since f is a polynomial, it is differentiable on sa, bd and continuous on fa, bg. Thus, by

Rolle’s Theorem, there is a number c between a and b such that f 9scd − 0. But

f 9sxd − 3x 2 1 1 > 1

for all x

_2

2

(since x 2 > 0) so f 9sxd can never be 0. This gives a contradiction. Therefore the equation

can’t have two real roots.

n

FIGURE 2

_3

The Mean Value Theorem is an

example of what is called an existence

theorem. Like the Intermediate Value

Theorem, the Extreme Value Theorem,

and Rolle’s Theorem, it guarantees that

there exists a number with a certain

property, but it doesn’t tell us how to

find the number.

Our main use of Rolle’s Theorem is in proving the following important theorem,

which was first stated by another French mathematician, Joseph-Louis Lagrange.

The Mean Value Theorem Let f be a function that satisfies the following

hypotheses:

1. f is continuous on the closed interval fa, bg.

2. f is differentiable on the open interval sa, bd.

Then there is a number c in sa, bd such that

1 f sbd 2 f sad

f 9scd −

b 2 a

or, equivalently,

2 f sbd 2 f sad − f 9scdsb 2 ad

Before proving this theorem, we can see that it is reasonable by interpreting it geometrically.

Figures 3 and 4 show the points Asa, f sadd and Bsb, f sbdd on the graphs of two

dif ferentiable functions. The slope of the secant line AB is

3 m AB −

f sbd 2 f sad

b 2 a

which is the same expression as on the right side of Equation 1. Since f 9scd is the slope of

the tangent line at the point sc, f scdd, the Mean Value Theorem, in the form given by Equation

1, says that there is at least one point Psc, f scdd on the graph where the slope of the

tangent line is the same as the slope of the secant line AB. In other words, there is a point

P where the tangent line is parallel to the secant line AB. (Imagine a line far away that

stays parallel to AB while moving toward AB until it touches the graph for the first time.)

y

P{c, f(c)}

y

B

A{a, f(a)}

A

P

B{b, f(b)}

0 a c b x

0 a c¡ c b x

FIGURE 3 FIGURE 4

Copyright 2016 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!