10.06.2022 Views

James Stewart-Calculus_ Early Transcendentals-Cengage Learning (2015)

A five star textbook for college calculus

A five star textbook for college calculus

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

1096 chapter 16 Vector Calculus

y

0

C

D

x

Green’s Theorem gives the relationship between a line integral around a simple closed

curve C and a double integral over the plane region D bounded by C. (See Figure 1. We

assume that D consists of all points inside C as well as all points on C.) In stating Green’s

Theorem we use the convention that the positive orientation of a simple closed curve C

refers to a single counterclockwise traversal of C. Thus if C is given by the vector function

rstd, a < t < b, then the region D is always on the left as the point rstd traverses C.

(See Figure 2.)

FIGURE 1

y

y

C

D

D

C

0

x

0

x

FIGURE 2

(a) Positive orientation

(b) Negative orientation

Recall that the left side of this equation

is another way of writing y C

F dr,

where F − P i 1 Q j.

Green’s Theorem Let C be a positively oriented, piecewise-smooth, simple

closed curve in the plane and let D be the region bounded by C. If P and Q have

continuous partial derivatives on an open region that contains D, then

y P dx 1 Q dy −

C

y y S −Q

−x 2 −P dA

−yD

D

Note The notation

y P dx 1 Q dy

C

or g P dx 1 Q dy

C

is sometimes used to indicate that the line integral is calculated using the positive orientation

of the closed curve C. Another notation for the positively oriented boundary curve

of D is −D, so the equation in Green’s Theorem can be written as

1 yy S −Q

−x 2 −P dA −

−yD y P dx 1 Q dy

−D

D

Green’s Theorem should be regarded as the counterpart of the Fundamental Theorem

of Calculus for double integrals. Compare Equation 1 with the statement of the Fundamental

Theorem of Calculus, Part 2, in the following equation:

y b

F9sxd dx − Fsbd 2 Fsad

a

In both cases there is an integral involving derivatives (F9, −Qy−x, and −Py−y) on the left

side of the equation. And in both cases the right side involves the values of the original

functions (F, Q, and P) only on the boundary of the domain. (In the one-dimensional case,

the domain is an interval fa, bg whose boundary consists of just two points, a and b.)

Copyright 2016 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).

Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!