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Teoria de Perturbações Invariantes de Calibre em ... - CBPFIndex

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então a hamiltoniana será levada <strong>em</strong><br />

{<br />

H=N − l2 P 2 a<br />

4aV + P T 1 ∫<br />

a 3λ+ d 3 x π2<br />

2a γ 1 2<br />

+ λ 2a<br />

( l<br />

+18l 4 α 2 a 1−6λ + 6l 2 a 1−3λ 2 P a ∂α<br />

4aV∂a + l2 P 2 a<br />

8a 2 V<br />

+ 2√ λ √ V √ ∫<br />

(λ+1)P T<br />

a 1 2 (1−3λ)<br />

l 2 P a<br />

∫ {[ 72α<br />

+ d 3 2 (λ+1)P T V<br />

xψ<br />

P 2 aλ<br />

+ l2 P 2 a ∂α<br />

8a 2 − 3λP T ∂α<br />

)<br />

V∂ ˜P a 2a 1+3λ ∂ ˜P a<br />

[<br />

+ − 3(1−2λ)√ (λ+1)P T<br />

2 √ λ √ V<br />

+ 6√ √<br />

V[(λ+1)P T ] 2<br />

3 λ<br />

l 2 P 2 a<br />

∫<br />

∂α<br />

− 3λP T<br />

∂ ˜P a<br />

√<br />

d 3 xγ 2 1 λ vψ i i−<br />

2<br />

[<br />

d 3 xγ 2 1 v i v i + − 9l2 λ(λ+1)P T<br />

a −(2+3λ)<br />

4V<br />

∂α<br />

)]∫<br />

2a 1+3λ d<br />

∂ ˜P 3 xγ 2 1 v<br />

2<br />

a<br />

3l 2√ (λ+1)P T<br />

√<br />

V<br />

a 4−9λ + 24(λ+1)P T V<br />

( l<br />

l 2 P 2 a 2(2−3λ) 2 P a ∂α<br />

aλ<br />

4aV∂a<br />

− 9[(λ+1)P T ] 2<br />

l 2 P 2 a<br />

]γ 1−6λ 2 1 ψ<br />

a<br />

a − 1 2 (1+3λ) − 6√ λ √ V √ (λ+1)P T P T<br />

l 2 P 2 a<br />

a 1 2 (1−9λ) + 12α√ V √ (λ+1)P T<br />

P a<br />

√<br />

λ<br />

a 3 2 (1−3λ) ]<br />

π<br />

a 1 2 (1−9λ)<br />

[<br />

+ − 72l2 α 2√ √<br />

(λ+1)P T V<br />

√ a 2 5 (1−3λ) + 9√ λ[(λ+1)P T ] 2<br />

3<br />

√ a − 2 1 (1+9λ)<br />

P a λ VPa<br />

− 24√ √<br />

(λ+1)P T V<br />

(<br />

√ a 1 l<br />

2 (5−9λ) 2 P a ∂α<br />

P a λ 4aV∂a + l2 P 2 a ∂α<br />

8a 2 − 3λP T ∂α<br />

)]<br />

V∂ ˜P a 2a 1+3λ γ 2 1 v<br />

∂ ˜P a<br />

[ a<br />

+<br />

2(λ+1)P 3l 2− T V<br />

l 4 P 2 a<br />

− 6l2 α<br />

a 2−3λ ]<br />

γ 1 2 ψ<br />

i i + 3(λ+1)P T<br />

P a<br />

a −(1+3λ) π ψ<br />

}<br />

[<br />

+<br />

a 3λ − 3(λ+1)P T<br />

a −(1+3λ) + (1−3λ)l2 P a<br />

P<br />

∫ ∫ a<br />

4a 2 V<br />

−N d 3 xφφ 6 + d 3 xλ φ π φ +λ N P N +λ µ P µ .<br />

]∫<br />

}<br />

d 3 xvπ<br />

a − 1 2 (5+3λ) ∫<br />

Nas expressões acima,αéuma função <strong>de</strong> a, P a e P T ainda in<strong>de</strong>terminada. Po<strong>de</strong>mos<br />

então usá-la <strong>de</strong> forma a anular o termo <strong>em</strong> vπ. Escolhendoαcomo<br />

α=− (λ+1)P T<br />

2l 2 ˜ P a a<br />

+ (1−3λ) ˜<br />

24V<br />

P a<br />

a −(2−3λ)<br />

d 3 xvπ ψ<br />

76

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