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A Manual of the Chemistry of the Carbon Compounds

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TUB CARBON COMPOUNDS. 27<br />

= 2*1 parts, or 2 atoms <strong>of</strong> hydrogen,<br />

v oA<br />

no » 217 parts, or 2 atpms <strong>of</strong> silver.<br />

In <strong>the</strong> yellow salt we find—<br />

--•!•,*," = 1-05 parts <strong>of</strong> hydrogen,<br />

62 '° x ^ 4 = 327-5 parts, or 3 atoms <strong>of</strong> silver.<br />

io-y<br />

From this we conclude that <strong>the</strong> acid is tribasic, and that <strong>the</strong><br />

formula C7H4O7 represents a molecule; and, as a fur<strong>the</strong>r confirmation,<br />

we find that we also know acid salts containing only one atom <strong>of</strong> a<br />

monad metal The molecular formulas <strong>of</strong> <strong>the</strong> above compounds are<br />

<strong>the</strong>refore— Meconic acid . . . . . C7H4O7<br />

White salt C^AggO,<br />

Yellow salt CjHAggO,<br />

A great number <strong>of</strong> carbon compounds containing nitrogen are<br />

bases, which combine with acids like ammonia; some are monacid<br />

bases, o<strong>the</strong>rs are polyacid. To fiud <strong>the</strong> molecular weight <strong>of</strong> such a<br />

compound, we have only to ascertain <strong>the</strong> quantity <strong>of</strong> acid contained<br />

in an anhydrous normal salt, or, better still, to find <strong>the</strong> quantity, <strong>of</strong><br />

platinum present in <strong>the</strong> double salts, formed by <strong>the</strong> combination <strong>of</strong><br />

<strong>the</strong> hydrochloride "with platinic chloride, and which, like ammoniumplatinic<br />

chloride, contain two molecules <strong>of</strong> hydrochloric acid for each<br />

molecule <strong>of</strong> platinio chloride.<br />

Caffeine is a monacid base; its platinum double salt contains two<br />

molecules <strong>of</strong> caffeine, and two molecules <strong>of</strong> hydrochloric acid, combined<br />

with one molecule <strong>of</strong> platinio chloride; 100 parts <strong>of</strong> this compound<br />

leave on ignition 24-6 per cent, <strong>of</strong> platinum; consequently, to find<br />

out in how much <strong>of</strong> <strong>the</strong> platinum salt one atom or 197*5 parts <strong>of</strong><br />

platinum are contained, we have—<br />

197-5 xlOO_ 9<br />

24-6 '<br />

From thU we find <strong>the</strong> molecular weight<strong>of</strong> vaffeine by <strong>the</strong> equation—<br />

2» + (2 x 36-5) + 339-5 = 806-9<br />

x = 197-2.<br />

As we know <strong>the</strong> percentage composition <strong>of</strong> this base, we can easily<br />

find its molecular formula:—<br />

197-2x49-5 ana „ .<br />

——Y7>»5— ~ 97'6 <strong>of</strong> carbon.<br />

— 7 '\*0 5 ' 2 - 103 <strong>of</strong> hydrogen.<br />

197-2x28-9 KIyft , ..<br />

JQQ— a 570 <strong>of</strong> nitrogen.<br />

1072 x 164 rtO„ .<br />

j-00 = 32-3 <strong>of</strong> oxygen.

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