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A Manual of the Chemistry of the Carbon Compounds

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TBB CARBON COMPOUNDS. 31<br />

On replacing <strong>the</strong> chlorine by hydroxyl we obtain e<strong>the</strong>ne alcohol:—<br />

CHj.OH<br />

CH,.OH<br />

The constitution <strong>of</strong> <strong>the</strong> e<strong>the</strong>ne compounds may also be expressed<br />

in a more simple way, thus:—<br />

which means that both <strong>the</strong>se compounds contain <strong>the</strong> dyad radical<br />

e<strong>the</strong>ne.<br />

E<strong>the</strong>ne alcohol yields by oxidation glycollic acid, a compound<br />

which can also be obtained from acetic acid. By <strong>the</strong> action <strong>of</strong> chlorine<br />

on <strong>the</strong> latter compound, chloracetic acid is formed, one atom <strong>of</strong><br />

chlorine substituting one atom <strong>of</strong> hydrogen in <strong>the</strong> group CEL When<br />

OFT Cl CO }<br />

cliloracetic acid ^ n a u • ^ V 0 is acted upon by caustic potash, <strong>the</strong><br />

chlorine is replaced by hydroxyl, and potassium chloride and glycollic<br />

acid are formed:—<br />

CHaCl. CO ) 0 + KOH = CH^OH) CO j Q + KC1<br />

By fur<strong>the</strong>r oxidation <strong>of</strong> glyeollic acid we obtain oxalic acid, <strong>the</strong><br />

two remaining atoms <strong>of</strong> hydrogen <strong>of</strong> <strong>the</strong> e<strong>the</strong>ne being substituted<br />

by oxygen. The constitution <strong>of</strong> <strong>the</strong>se different acids we may<br />

represent thus:—<br />

Chloracetio Glycollio Oxalic<br />

Aoid. Acid. Aoid.<br />

CH^Cl CHg.OH CO. OH<br />

CO. OH CO.OH CO. OH<br />

In some cases it is convenient to resolve such amstUtttional<br />

formulas still fur<strong>the</strong>r, in order to explain oases <strong>of</strong> isomerism, &c. In<br />

order to do this we may represent <strong>the</strong> quantivalence <strong>of</strong> elements by<br />

straight lines, thus;—<br />

Hydrogim. Oxygen. Nitrogen. <strong>Carbon</strong>.<br />

H— —0-<br />

A ' 4 ~<br />

And by aid <strong>of</strong> <strong>the</strong>se symbols <strong>the</strong> following graphical formulte are<br />

arrived at:— Ethane. Ethylamine.<br />

H H H H<br />

H—C C~H H-h C-N 7

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