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M-Maxâ„¢ Series Adjustable Frequency Drive - Eaton Corporation

M-Maxâ„¢ Series Adjustable Frequency Drive - Eaton Corporation

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Parameters<br />

On the constant three-phase AC supply, the three-phase<br />

asynchronous motor has a constant rotor speed (n1 , P7.3,<br />

rating plate specifications) according to the number of pole<br />

pairs and input frequency. The slip here represents the<br />

difference between the rotating field of the stator and that of<br />

the rotor. In static operation, the slip is constant.<br />

Load changes [1] at the motor shaft cause a larger slip ( n)<br />

and thus a reduced rotor speed [2]. In controlled operation<br />

(V/f-characteristic), the frequency inverter cannot<br />

compensate this load-related speed difference. The speed<br />

behavior of the motor is even, as in a constant AC supply.<br />

Speed Behavior without Slip Compensation<br />

M<br />

M 2<br />

M 1<br />

n 2<br />

n<br />

n1 In “Speed control” mode (P11.8 = 1), the frequency inverter<br />

can compensate these load-related deviations. From the<br />

measured voltage and current values of the stator winding<br />

(u 1 , i 1 ) the internal motor model calculates the required<br />

manipulated variables for the flux variable i μ and the torque<br />

variable i w . In the equivalent circuit diagram of the<br />

three-phase motor, the load-related slip is shown as the<br />

resistance R’ 2 /s. In idle operation without a load, this<br />

resistance approaches infinity, and approaches zero as the<br />

load increases.<br />

2<br />

1<br />

108 M-Max <strong>Series</strong> <strong>Adjustable</strong> <strong>Frequency</strong> <strong>Drive</strong> MN04020003E—April 2011 www.eaton.com<br />

n<br />

Equivalent Circuit Diagram for an Asynchronous Motor<br />

X 1<br />

i 1<br />

R 1<br />

Item<br />

Number Description<br />

1 Stator winding<br />

2 Air gap<br />

3 Transformed rotor winding<br />

An exact calculation requires the precise rating specifications<br />

of the motor (parameter group 7). The speed control (P11.8 =<br />

1) can then compensate the load-related slip deviations. The<br />

simple illustration shows that, as the load torque increases<br />

[1], the resulting speed reduction is compensated by an<br />

increase in the output frequency [2] (see figure below).<br />

X' 2<br />

Speed Behavior with Slip Compensation<br />

M<br />

u 1<br />

M 2<br />

M 1<br />

i m<br />

X h<br />

i w<br />

1 2 3<br />

2<br />

1<br />

n 1<br />

n<br />

R' 2<br />

s

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