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Principles of naval engineering - Historic Naval Ships Association

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PRINCIPLES OF NAVAL ENGINEERINGIn other words, maximum work is obtainedfrom a reversing blade when the blade velocityis exactly one-half the absolute velocity <strong>of</strong> thesteam at the blade entrance.^ The maximumamount <strong>of</strong> work obtainable from a reversingblade is twice the amount obtainable from theflat vane shown in figure 12-3.In actual turbines, it is not feasible toutilize the complete reversal <strong>of</strong> steam in theblades, since to do so would require that thenozzle be placed in a position that would alsobe swept by the blades— an obvious impossibility.Furthermore, if the steam enteredthe blade tangent ially it would not be carriedthrough the turbine axially (longitudinally). However,it is only the tangential component <strong>of</strong> thesteam velocity that produces work on the turbineblades; hence the nozzle angle is made assmall as possible.As we know, the work done on the blade mustequal the total energy entering minus the totalenergy leaving. The velocity diagram for animpulse turbine shown in figure 12-5 providesa way <strong>of</strong> determining the work done on theblade in terms <strong>of</strong> the various velocities andangles.The tangential component (which is the onlycomponent that produces work) <strong>of</strong> the velocity<strong>of</strong> the entering steam isVj cos awhich is also equal toVb + Ri cos bThe tangential component <strong>of</strong> the velocity <strong>of</strong>the departing steam isfrom Vj^ cos a, the resultant velocity may beexpressed asor, alternatively, asVj^ cos a - V2 cos cRj cos b + R2 cos dAssuming a steam flow <strong>of</strong> W pounds persecond,andWWmass per secondforceTherefore, the force on the blade isWF, = — (Ri cos b + R2 cos d) pounds__W(Yj^ pQg 3 _y^ cos c) poundsWork is force through distance. Therefore,the rate <strong>of</strong> doing work on the blade isWkb =FfaVb= W(R^ c°^b+R2 cos d) Vjj foot-pounds^ per second= g-^'^icos a - V2 cos c) Vjj footpoundsper secondwhich isV2 cos calso equal toVjj - R2 cos dNOZZLE V,"steam jetSince entering and leaving velocities areopposed to each other if V2 cos c is in the samedirection as V^ cos a, and supplementary toeach other if V2 cos c is in the opposite directionThis statement assumes, <strong>of</strong> course, that the nozzleIs tangential to the blades. In actual impulse turbines,the maximum amount <strong>of</strong> work is done when the bladespeed is one-half the cosine <strong>of</strong> the nozzle angle timesthe absolute velocity <strong>of</strong> the entering steam.BLADES147.92Figure 12-3.—Elementary impulse turbine.322

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