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Principles of naval engineering - Historic Naval Ships Association

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wPRINCIPLES OF NAVAL ENGINEERINGExample : Add four gun mounts topside to aship with the curves <strong>of</strong> form shown in figure3-25. Assume an initial KG <strong>of</strong> 24.5 feet. Assumethat the gun mounts weigh 28 tons each and thattheir center <strong>of</strong> gravity is located 48 feet abovethe keel. What is the effect on stability?1. New displacement = W+ w= 11,500+ (4 x28) =11,612 tons.2. New mean draft = 19.7 feet (fig. 3-25).wz3. GGi = W+w= 4 X 28= 112 tonsz =48 - 24.5 =23.5 feet112 X 23.5GGi = 11,6120.23 feet4. KG^ = 24,50 +0.23 = 24.73 feet.5. New KMj = 28.4 feet (fig. 3-25).6. New GiMi = KM^ - KGi = 28.43.7 feet.- 24.7=7. The values for the angles (0 °— 70°) aretaken from the cross curves for 11,612tons displacement (fig. 3-14). KA is 20 feet.Corrections are made for AGi x sini? =(24.73 - 20) sin(9=4.73 sinS. The correctionsare applied to the curve (fig. 3-26)as previously explained. Figure 3-26shows the curve <strong>of</strong> righting arms correctedfor weight addition,HORIZONTAL WEIGHT CHANGESIn the previous example <strong>of</strong> weight addition,suppose the gun mounts are located with theircenter <strong>of</strong> gravity 29 feet to starboard <strong>of</strong> thecenterline and the weight is moved athwartshipto its final <strong>of</strong>f-center location. The shift in Gmay be found by using the proper formula, makingthe required corrections, and applying thecorrections to the curve in figure 3-26. Thisgives a correct curve <strong>of</strong> righting arms. Toobtain a curve <strong>of</strong> righting moments, the rightingarms are multiplied by the new displacement(W+w) = 11,612 tons, and plotted in figure 3-27.WEIGHT REMOVALThe results <strong>of</strong> a weight removal are computedby using the previous procedure, the onlydifference being that most <strong>of</strong> the operationsand results will be found just the reverse <strong>of</strong>those which relate to adding a weight.EFFECTS OF LOOSE WATERWhen a tank or a compartment in a ship ispartially full <strong>of</strong> liquid that is free to move asthe ship heels, the surface <strong>of</strong> the liquid tends toremain level. The surface <strong>of</strong> the free liquid isreferred to as free surface . The tendency <strong>of</strong> theliquid to remain level as the ship heels is referredto as free surface effect . The term loosewater is used to describe liquid that has a freesurface; it is not usedtodescribe water or otherliquid that completely fills a tank or compartmentand thus has no free surface.FREE SURFACE EFFECTFree surface in a ship always causes a reductionin GM with a consequent reduction <strong>of</strong>stability, superimposed on any additional weightwhich would be caused by flooding. The flow <strong>of</strong>the liquid is an athwartship shift <strong>of</strong> weight whichvaries with the angle <strong>of</strong> inclination. Whereverfree surface exists, a free surface correctionmust be applied to any stability calculation. Thiseffect may be considered to cause a reduction ina ship's static stability curve in the amount <strong>of</strong>where4i-x sin^, due to a virtual rise inGi = the moment <strong>of</strong> inertia <strong>of</strong> the surface <strong>of</strong>water in the tank about a longitudinal axisthrough the center <strong>of</strong> area <strong>of</strong> that surface(or other liquid in ratio <strong>of</strong> its specificgravity to that <strong>of</strong> the liquid in which theship is floating)^V = existing volume <strong>of</strong> displacement <strong>of</strong> theship in cubic feet. For a rectangular compartment,i may be found fromwhereb^i12"b= athwartship breadth <strong>of</strong> the free surface(with the ship upright) in feet1= fore-and-aft length <strong>of</strong> the free surface infeetIt is usual to assume all liquids are salt water, andthus neglect density, unless very accurate determinationsare required.52

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