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PES Skill Sheets.book - Capital High School

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<strong>Skill</strong> Sheet 14.1: Chemical Equations<br />

Part 1 answers: Part 2 answers:<br />

Reactants<br />

Hydrochloric acid<br />

HCl and<br />

Sodium hydroxide<br />

NaOH<br />

Calcium carbonate<br />

CaCO3 and<br />

Potassium iodide<br />

KI<br />

Aluminum<br />

fluoride<br />

AlF3 and<br />

Magnesium nitrate<br />

Mg(NO3) 2<br />

Products<br />

Water<br />

H2O and<br />

Sodium chloride<br />

NaCl<br />

Potassium<br />

carbonate<br />

K2CO3 Calcium iodide<br />

CaI2 Aluminum nitrate<br />

Al(NO3 ) 3<br />

and Magnesium<br />

fluoride<br />

MgF2 Unbalanced Chemical Equation<br />

HCl + NaOH → NaCl + H20 CaCO3 + KI → K2CO3 + CaI2 AlF3 + Mg(NO3 ) 2 → Al(NO3 ) 3<br />

+ MgF2 1. 4Al + 3O2 → 2Al2O3 2. CO + 3H2 → H2O + CH4 3. 2HgO → 2Hg + O2 4. CaCO3 → CaO + CO2 5. 3C + 2Fe2O3 → 4Fe + 3CO2 6. N2 + 3H2 → 2NH3 7. 2K+ 2H2O → 2KOH + H2 8. 4P + 5O2 → 2P2O5 9. Ba(OH) 2 + H2SO4 → 2H2O + BaSO4 10. CaF2 + H2SO4 → CaSO4 + 2HF<br />

11. 4KClO3 → 3KClO4 + KCl<br />

<strong>Skill</strong> Sheet 14.1: The Avogadro Number<br />

Substance Elements in<br />

substance<br />

Atomic<br />

masses of<br />

elements<br />

(amu)<br />

<strong>Skill</strong> Sheet 14.1: Formula Mass<br />

Part 1 answers:<br />

1. First ion: Ca +2 ; Second ion: PO 4 3–<br />

2. Ca 3 (PO 4 ) 2<br />

3.<br />

No. of<br />

atoms of<br />

each<br />

element<br />

<strong>Skill</strong> Sheet 14.2: Classifying Reactions<br />

Formula<br />

mass<br />

(amu)<br />

Molar<br />

mass<br />

(g)<br />

Sr Sr 87.6 1 87.6 87.6<br />

Ne Ne 20.2 1 20.2 20.2<br />

Ca(OH) 2 Ca, O, H Ca, 40.1<br />

0, 16.0<br />

1<br />

2<br />

74.1 74.1<br />

H, 1.01 2<br />

NaCl Na, Cl Na, 23.0 1 58.5 58.5<br />

Cl, 35.5 1<br />

O3 O 16.0 3 48.0 48.0<br />

C6H12O C, H, O C, 12.0<br />

H, 1.01<br />

6<br />

12<br />

100 100<br />

O; 16.0 1<br />

Atom Quantity Atomic mass<br />

Total mass<br />

(from periodic table) (number × atomic mass)<br />

Ca 3 40.08 120.24<br />

P 2 30.97 61.94<br />

O 8 16.00 128.00<br />

1. Synthesis. Two substances combine to make a new compound.<br />

2. Single displacement. Chlorine replaces potassium in the<br />

compound.<br />

3. Decomposition. A single compound is broken into two<br />

substances.<br />

4. Decomposition. A single compound is broken into two<br />

substances.<br />

5. Combustion. A carbon compound reacts with oxygen to<br />

produce carbon dioxide and water.<br />

6. Double displacement. Two solutions are mixed and a solid is<br />

one of the products.<br />

7. Double displacement. Two solutions are mixed and a solid is<br />

one of the products.<br />

8. Single displacement. Sodium replaces calcium in the compound.<br />

Page 34 of 57<br />

Substance Molar mass<br />

(g)<br />

Mass of sample<br />

(g)<br />

Number of particles<br />

present<br />

MgCO3 84.32 12.75 9.10 × 1022 H2O 18.02 8.85 × 1029 296 × 1050 N2 28.02 3.30 × 10-14 7.1 × 108 Yb 173.04 0.00038 1.3 × 10 18<br />

Al2 (SO3 ) 3 294.17 4657 9.53 × 1024 K2CrO4 194.20 0.00074 0.23 × 10 19<br />

4. The formula mass for Ca3 (PO4 ) 2 : 120.24 g + 61.94 g +<br />

128.00 g = 310.18 g<br />

Part 2 answers:<br />

1.<br />

2.<br />

3.<br />

4.<br />

BaCl2 NaHCO3 Mg(OH) 2<br />

NH4NO3 formula mass:<br />

formula mass:<br />

formula mass:<br />

formula mass:<br />

208.23<br />

84.01<br />

58.33<br />

80.06<br />

5. Sr3(PO4) 2 formula mass: 452.80<br />

9. Decomposition. A single compound is broken into two<br />

substances.<br />

10. Combustion. A carbon compound reacts with oxygen to<br />

produce carbon dioxide and water.<br />

11. This is a double displacement reaction because a solid forms<br />

from two solutions.<br />

12. A combustion reaction.<br />

13. Synthesis reaction because two substances form a single<br />

compound.<br />

14. The reaction is similar to a combustion reaction because a<br />

substance (hydrogen) reacts with oxygen and energy is<br />

produced. So is water. It is different because carbon is not<br />

involved in the reaction.

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