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Contoh Soal<br />

1. Hitung kelarutan garam AgCl dalam air, jika K sp<br />

AgCl = 1,8.10 -10 .<br />

Penyelesaian:<br />

Misal kelarutan AgCl = X mol L –1<br />

AgCl(s) Ag + (aq) + Cl – (aq)<br />

X X X<br />

K sp<br />

AgCl = [Ag + ][Cl – ]<br />

1,8.10 -10 = (X) x (X) = X 2<br />

x = <br />

18 , . 10 10 = 1,3.10 -5 mol L –1<br />

Kelarutan AgCl = 1,3.10 -5 mol L –1 .<br />

2. Suatu mineral mengandung kalsium fluorida CaF 2<br />

. Hitung kelarutan garam<br />

tersebut (g L –1 ) jika K sp<br />

CaF 2<br />

= 3,9.10 -11 .<br />

Penyelesaian:<br />

Misalkan [CaF 2<br />

] = X mol L –1<br />

CaF 2<br />

(s) Ca 2+ (aq) + 2F – (aq)<br />

X X 2X<br />

K sp<br />

CaF 2<br />

= [Ca 2+ ][F – ] 2<br />

= (X) x (2X) 2<br />

= 4X 3<br />

4X 3 = 3,9.10 -11<br />

X =<br />

3 3910 , . 11<br />

4<br />

X = 2,1363.10 -4 mol L –1<br />

= 2,1363.10 –4 mol L –1<br />

Kelarutan CaF 2<br />

= (2,1363.10 -4 mol L –1 ) x 78 = 1,67.10 -2 g L –1 .<br />

3. Dalam suatu eksperimen 1,2.10 -3 mol PbI 2<br />

terlarut dalam 1 liter larutan pada<br />

suhu 25C. Berapa harga K sp<br />

nya?<br />

Penyelesaian:<br />

PbI 2<br />

(s) Pb 2+ (aq) + 2I – (aq)<br />

1,2.10 -3 2,4.10 -3<br />

K sp<br />

PbI 2<br />

= [Pb 2+ ][I – ] 2<br />

= (1,2.10 -3 ) x (2,4.10 -3 ) 2<br />

= 6,912.10 -9<br />

4. Kelarutan kalsium oksalat adalah 0,0061 g L –1 larutan. Hitung berapa harga<br />

K sp<br />

CaC 2<br />

O 4<br />

(A r<br />

Ca = 40, C = 12, O = 16).<br />

Kelarutan dan Hasil Kali Kelarutan 239

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