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STOCHASTIC

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But now,<br />

EFFICIENCY ANALYSIS OF CHOICES INVOLVING RISK 337<br />

f 0, due to the right-continuity of F and G,<br />

there is an interval x0 gx< x0+/J where G(x)-F(x)>0. To show that there exist some<br />

u0 for which AFuo>0, choose u0(x) as follows:<br />

{ x0<br />

x g x0<br />

x x0 S x S x0+P<br />

X0+P X g X0+P.<br />

Then u0 6 U, and (G - F)du = | ° (G - F)dx > 0.<br />

(6) The necessity is proved similarly. If, for some xu G(x1)-F(x1)

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