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STOCHASTIC

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PSEUDO-CONVEX FUNCTIONS 283<br />

PROPERTY 1. Let C be convex. If 8(x) is convex on C, then 6(x) is pseudoconvex<br />

in C, but not conversely.<br />

Proof. If 8(1) is convex on C, then by (1.4),<br />

(x 2 - x'YvJix 1 ) & 0 implies B(x 2 ) S 9(x'),<br />

which is precisely (1.1). That the converse is not necessarily true can be<br />

seen from the example<br />

$(x) = x + x\ x (= E\<br />

which is pseudo-convex on A' 1 but not convex. 1<br />

PROPERTY 2. Let C be convex. If B(x) is pseudo-convex on C, then B(x) is<br />

strictly quasi-convex (and hence quasi-convex) on C, but not conversely.<br />

Proof. Let 0(x) be pseudo-convex on C. We shall assume that 9(x) is not<br />

strictly quasi-convex on C and show that this leads to a contradiction. If<br />

B(x) is not strictly quasi-convex on C, then it follows from (1.7) that there<br />

exist x l ?* x 2 in C such that<br />

(2.1) 0{x 2 ) < 8(x y ),<br />

and<br />

(2.2) B(x) £ B{x'),<br />

for some iCL, where<br />

(2.3) L = \x | x = Xx 1 + (1 - A)x 2 , 0 < A < l\.<br />

Hence there exists an x £ L such that<br />

(2.4) 6(x) = max 8{x),<br />

where<br />

(2.5) L = LU\x l ,x 2 }.<br />

Now define<br />

(2.6) /(A) = «((1 - \)x l + Xx 2 ), 0SJS1.<br />

Hence<br />

(2.7) 9(x) = /(A),<br />

where<br />

(2.8) x = (1 - X)z' + Xx 2 , 0 < X < 1.<br />

1 To see that x + a: 3 is pseudo-convex, note that Vxd(x) = 1 + 3x 2 > 0. Hence<br />

(l - i^'V^x") jg 0 implies that x & x° and x 3 i (x')', and thus<br />

$(x) - 9(3°) = Or + x') - (i° + (x°)') g 0.<br />

CONVEXITY AND THE KUHN-TUCKER CONDITIONS

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