06.06.2013 Views

STOCHASTIC

STOCHASTIC

STOCHASTIC

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

R. G. VICKSON<br />

for distinct i, j, and /. Assuming that 0 < kt < u'(0) for / = 1, ...,n (which is<br />

always possible by suitable choice of p), it follows that y (k) will actually be an<br />

interior solution for all k g 1. Since (22) holds as an identity in k and kt, it<br />

is permissible to set k = 1, to fix kj and kt at arbitrary values in the interval<br />

(0, K'(0)), and to let z = k{ be a variable. Then (22) becomes<br />

rx z 2 g"(z) + r2 zg'(z) + r3g(z) = 0 (23)<br />

for real constants r1; r2, and r3. It is easy to verify that, if a and /? are the<br />

roots of the quadratic equation<br />

then the general solution to (23) is<br />

rlx{x-\) + r2x + r3 = 0, (24)<br />

(Az" + Bz f if a*P,<br />

9(z) = (25)<br />

\z*(A + Blogz) if a = p,<br />

with constant A and B. Note that g(z) must have the form (25) in each interval<br />

within which g" is continuous. Although it might seem that g could be made up<br />

from different "pieces" of the form (25), with constants A, B, a, and /?<br />

changing, this is, in fact, not true. The reader can verify that separation,<br />

together with the assumed continuity of g and g', implies that the single set<br />

of constants A ,B, a, fi applies throughout the entire subdomain {z\z< u'(0)}.<br />

In terms of u, this means that the following functional representation holds:<br />

_ (Au'ffl + Bu'tfY (a # P), (26a)<br />

" (u'(Zr IA + B log «'(0] (« = P) (26b)<br />

for all £ e (0, oo). Note that separation forces u to be three times continuously<br />

differentiable on (0, oo), even though this was originally assumed to be true<br />

only in a piecewise sense.<br />

For problem Pk with 0 g k < n, the reader can show that Eqs. (26a) and<br />

(26b) are valid throughout the entire domain £ e (u, oo) of u, even if u < 0.<br />

In fact, it is always possible to construct a nonsingular matrix p such that all<br />

relevant nonnegativity constraints are satisfied strictly, while the unconstrained<br />

assets are sold short, so that g(z) is "probed" for ze(u,0). However, if<br />

k = n, the nonnegativity constraints form a natural boundary which always<br />

restricts £ in (26) to the set (0, oo). In this case, even if u < 0, no information<br />

about the behaviour of M(^) for £ < 0 can be obtained from the portfolio<br />

problem. The following fundamental theorem of Cass and Stiglitz has thus<br />

been proved.<br />

162 PART II QUALITATIVE ECONOMIC RESULTS

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!