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Processus de Lévy en Finance - Laboratoire de Probabilités et ...

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4.2. DEPENDENCE CONCEPTS FOR LEVY PROCESSES 139<br />

In view of the above lemma, for a giv<strong>en</strong> Lévy measure ν we will refer to the Lévy measure<br />

ν I <strong>de</strong>fined by Equation (4.5) as the I-margin of ν. To simplify notation, wh<strong>en</strong> I = {k} for some<br />

k, the I-margin of ν will be <strong>de</strong>noted by ν k and called simply k-th margin of ν.<br />

Next we would like to characterize the in<strong>de</strong>p<strong>en</strong><strong>de</strong>nce of Lévy processes in terms of their<br />

characteristic tripl<strong>et</strong>s.<br />

Lemma 4.2. The compon<strong>en</strong>ts X 1 , . . . , X d of an R d -valued Lévy process X are in<strong>de</strong>p<strong>en</strong><strong>de</strong>nt<br />

if and only if their continuous martingale parts are in<strong>de</strong>p<strong>en</strong><strong>de</strong>nt and the Lévy measure ν is<br />

supported by the coordinate axes. ν is th<strong>en</strong> giv<strong>en</strong> by<br />

ν(B) =<br />

d∑<br />

ν i (B i ) ∀B ∈ B(R d \ {0}), (4.2)<br />

i=1<br />

where for every i, ν i <strong>de</strong>notes the i-th margin of ν and<br />

B i = {x ∈ R : ( 0, . . . , 0<br />

} {{ }<br />

, x, 0, . . . , 0) ∈ B}.<br />

i − 1 times<br />

Proof. Since the continuous martingale part and the jump part of X are in<strong>de</strong>p<strong>en</strong><strong>de</strong>nt, we<br />

can assume without loss of g<strong>en</strong>erality that X has no continuous martingale part, that is, its<br />

characteristic tripl<strong>et</strong> is giv<strong>en</strong> by (0, ν, γ).<br />

The “if” part. Suppose ν is supported by the coordinate axes. Th<strong>en</strong> necessarily for every<br />

B ∈ B(R d \ {0}), ν(B) = ∑ d<br />

i=1 ˜ν i(B i ) with some measures ˜ν i , and Lemma 4.1 show that these<br />

measures coinci<strong>de</strong> with the margins of ν: ˜ν i = ν i ∀i. Using the Lévy-Khintchine formula for<br />

the process X, we obtain:<br />

∫<br />

E[e i〈u,Xt〉 ] = exp t{i〈γ, u〉 + (e i〈u,x〉 − 1 − i〈u, x〉1 |x|≤1 )ν(dx)}<br />

R d \{0}<br />

d∑<br />

∫<br />

= exp t {iγ k u k + (e iu kx k<br />

− 1 − iu k x k 1 |xk |≤1)ν k (dx k )} =<br />

k=1<br />

R\{0}<br />

which shows that the compon<strong>en</strong>ts of X are in<strong>de</strong>p<strong>en</strong><strong>de</strong>nt Lévy processes.<br />

d∏<br />

E[e iu kXt k ],<br />

The “only if” part. Define a measure ˜ν on R d \ {0} by ˜ν(B) = ∑ d<br />

i=1 ν i(B i ), where ν i is the<br />

i-th marginal Lévy measure of X and B i is as above. It is straightforward to check that ˜ν is<br />

a Lévy measure. Since the compon<strong>en</strong>ts of X are in<strong>de</strong>p<strong>en</strong><strong>de</strong>nt, applying the Lévy-Khintchine<br />

formula to each compon<strong>en</strong>t of X, we find:<br />

∫<br />

E[e i〈u,Xt〉 ] = exp t{i〈γ, u〉 +<br />

R d \{0}<br />

k=1<br />

(e i〈u,x〉 − 1 − i〈u, x〉1 |x|≤1 )˜ν(dx)}.

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