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Processus de Lévy en Finance - Laboratoire de Probabilités et ...

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5.2. SIMULATION OF DEPENDENT LEVY PROCESSES 175<br />

Proof. We must prove that for each A ∈ B(R d ),<br />

ν(A) = µ({u ∈ R d : f(u) ∈ A}),<br />

but in view of Lemma 4.7, it is suffici<strong>en</strong>t to show that for each I ⊂ {1, . . . , d} nonempty and<br />

for all (x i ) i∈I ∈ (R \ {0}) |I| ,<br />

U I ((x i ) i∈I ) = µ({u ∈ R d : U (−1)<br />

i<br />

(u i ) ∈ I(x i ), i ∈ I}),<br />

where I(x) was <strong>de</strong>fined in (4.21). However, since U i is left-continuous, for every i, U (−1)<br />

i<br />

(u) ∈<br />

I(x) if and only if u ∈ (U i (x) ∧ 0, U i (x) ∨ 0]. Therefore,<br />

µ({u ∈ R d : U (−1)<br />

i<br />

(u i ) ∈ I(x i ), i ∈ I})<br />

= µ({u ∈ R d : u i ∈ (U i (x i ) ∧ 0, U i (x i ) ∨ 0], i ∈ I}) = F I ((U i (x i )) i∈I ),<br />

and an application of Theorem 4.8 compl<strong>et</strong>es the proof.<br />

By Theorem 2.28 in [1], there exists a family, in<strong>de</strong>xed by ξ ∈ R, of positive Radon measures<br />

K(ξ, dx 2 · · · dx d ) on R d−1 , such that<br />

ξ ↦→ K(ξ, dx 2 · · · dx d )<br />

is Borel measurable and<br />

µ(dx 1 . . . dx d ) = λ(dx 1 ) ⊗ K(x 1 , dx 2 · · · dx d ). (5.7)<br />

In addition, K(ξ, R d−1 ) = 1 λ-almost everywhere, that is, K(ξ, ∗) is, almost everywhere, a probability<br />

distribution. In the sequel we will call {K(ξ, ∗)} ξ∈R the family of conditional probability<br />

distributions associated to the Lévy copula F .<br />

L<strong>et</strong> F ξ be the distribution function of the measure K(ξ, ∗):<br />

F ξ (x 2 , . . . , x d ) := K(ξ, (−∞, x 2 ] × · · · × (−∞, x d ]), (x 2 , . . . , x d ) ∈ R d−1 . (5.8)<br />

The following lemma shows that it can be computed in a simple manner from the Lévy copula<br />

F .

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