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Processus de Lévy en Finance - Laboratoire de Probabilités et ...

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2.1. LEAST SQUARES CALIBRATION 67<br />

is not continuous with respect to mark<strong>et</strong> data, these small errors may dramatically alter the<br />

result of calibration, r<strong>en</strong><strong>de</strong>ring it compl<strong>et</strong>ely useless. On the other hand, ev<strong>en</strong> if mark<strong>et</strong> data<br />

did not contain errors, in abs<strong>en</strong>ce of continuity, small daily changes in prices could lead to large<br />

variations of calibrated param<strong>et</strong>ers and of other quantities computed using these param<strong>et</strong>ers<br />

(like prices of exotic options).<br />

Wh<strong>en</strong> the calibration problem has more than one solution, care should be tak<strong>en</strong> in <strong>de</strong>fining<br />

what is meant by continuity. In the sequel, we will use the following <strong>de</strong>finition (see, e.g. [40]),<br />

that applies to all calibration problems, discussed in this chapter.<br />

Definition 2.1. The solutions of a calibration problem are said to <strong>de</strong>p<strong>en</strong>d continuously on input<br />

data at the point C M if for every sequ<strong>en</strong>ce of data s<strong>et</strong>s {C n M } n≥0 such that ‖C n M −C M‖ w −−−→<br />

n→∞ 0,<br />

if Q n is a solution of the calibration problem with data C n M th<strong>en</strong><br />

1. {Q n } n≥1 has a weakly converg<strong>en</strong>t subsequ<strong>en</strong>ce {Q nm } m≥1 .<br />

2. The limit Q of every weakly converg<strong>en</strong>t subsequ<strong>en</strong>ce of {Q n } n≥1 is a solution of the<br />

calibration problem with data C M .<br />

Note that if the solution of the calibration problem with the limiting data C M is unique, this<br />

<strong>de</strong>finition reduces to the standard <strong>de</strong>finition of continuity, because in this case every subsequ<strong>en</strong>ce<br />

of {Q n } has a further subsequ<strong>en</strong>ce converging towards Q, which implies that Q n ⇒ Q.<br />

It is easy to construct an example of mark<strong>et</strong> data leading to a least squares calibration<br />

problem (2.4) that does not satisfy the above <strong>de</strong>finition.<br />

Example 2.2. Suppose that S 0 = 1, there are no interest rates or divi<strong>de</strong>nds and the mark<strong>et</strong> data<br />

for each n are giv<strong>en</strong> by a single observation:<br />

C n M(T = 1, K = 1) = E[(e Xn 1 − 1) + ] for n ≥ 1 and C M (T = 1, K = 1) = 1 − e −λ ,<br />

where Xt<br />

n is <strong>de</strong>fined by Equation (2.8) and λ > 0. Th<strong>en</strong> ‖CM n −C M‖ w −−−→ 0 and<br />

n→∞ Xn t is clearly<br />

a solution for data CM n , but the sequ<strong>en</strong>ce {Xn t } has no converg<strong>en</strong>t subsequ<strong>en</strong>ce (cf. Proposition<br />

1.7).<br />

Un<strong>de</strong>r conditions, similar to those of Theorem 2.1, Lemmas 2.2–2.4 allow to prove a continuity<br />

result for the least squares calibration problem (2.4).

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