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Manual <strong>de</strong> operación <strong>de</strong> DVP-ES2/EX2/SS2/SA2/SX2 - Programación<br />

3. Asumir:<br />

(D10) = 0123 H ‘0’ = 30H ‘4’ = 34H ‘8’ = 38H<br />

3-236<br />

(D11) = 4567 H ‘1’ = 31H ‘5’ = 35H ‘9’ = 39H<br />

(D12) = 89AB H ‘2’ = 32H ‘6’ = 36H ‘A’ = 41H<br />

(D13) = CDEFH ‘3’ = 33H ‘7’ = 37H ‘B’ = 42H<br />

4. Cuando n es 2, la estructura <strong>de</strong> bit será como:<br />

D10=0123 H<br />

0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1<br />

0 1 2 3<br />

Código ASCII <strong>de</strong> "2" en D20 es 32H<br />

0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 0<br />

Código ASCII <strong>de</strong> "3" en D21 es 33H<br />

0 0 0 0 0 0 0 0 0 0 1 1 0 0 1<br />

3<br />

2<br />

3 3<br />

5. Cuando n es 4, la estructura <strong>de</strong> bit será como:<br />

b15 D10 = H 0123<br />

b0<br />

0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1<br />

b15 D20<br />

b0<br />

0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0<br />

0 H 30<br />

b15<br />

0 0<br />

0 1 2 3<br />

Convertido a<br />

D21<br />

b0<br />

0 0 0 0 0 0 0 0 1 1 0 0 0 1<br />

1 H 31<br />

b15 D22<br />

b0<br />

0 0 0 0 0 0 0 0 0 0 1 1<br />

0 0 1 0<br />

2 H 32<br />

b15 D23<br />

b0<br />

0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 1<br />

3 H 33<br />

1

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