Syllabus 2009

Exacte oplossing:8 2∫−45x− 2x+182dx = ⎡5x −4Bgtan x − ln2( x + 1)⎤ = 47,56979x + 1 ⎣⎦−4Oplossing (n = 6):b−a8 −( −4)h = = = 2n 68 2∫−45x− 2x+1 1dx =2.2. f − 4 + 2. f 0 + f 4 + 4. f − 2 + f 2 + f 6 + f 8x + 1 3( ( ) ( ( ) ( )) ( ( ) ( ) ( )) ( ))= 48,257405Procentuele fout ongeveer 1,4 %8 2∫−4Oplossing (n = 12):b−a8 −( −4)h = = = 1n 125x− 2x+1 1dx = f − + f − + f + + f + f − + f − + + f + f2x + 1 3( ( 4) 2. ( ( 2) ( 0 ) ... ( 6)) 4. ( ( 3) ( 1 ) ... ( 7)) ( 8))= 47,885709Procentuele fout ongeveer 0,66 %Probleem oplossend integreren met de TI-84 Plus66Philip Bogaert