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128 CAPÍTULO £ £ ¥ § § ¤§ ¢¢¡ ¤§<br />

12.<br />

(0, 0, 0) R (0, 3, 1) ¡ ¢ <br />

<br />

<br />

(x, y, z) = λ(0, 3, 1), λ ∈ IR<br />

R ¢ ¢ ¡ ©<br />

2x + y + z = 1 x − y − z + 2 = <br />

0<br />

R <br />

<br />

3x = −1 y + z = 1 − 2x ⇐⇒ x = − 1<br />

(x, y, z) ∈ R ⇐⇒ (x, y, z) = − 1 5 , y, 3 3 − y = − 1<br />

<br />

5 , 0, + y(0, 1, −1)<br />

3 3<br />

£¢<br />

<br />

1 − <br />

¢ <br />

<br />

x + 5y =<br />

<br />

2<br />

3<br />

, 0, 5<br />

3<br />

3<br />

3<br />

y + z = 5<br />

R (0, 1, −1) ¡ <br />

(x, y, z) = − 1<br />

<br />

5<br />

, 0, + λ(0, 1, −1), λ ∈ IR<br />

3 3<br />

¡ ¨ ¢ ¢ ©<br />

<br />

3x − 2y + 4z − 6 = 0<br />

<br />

¨¥ ¨ P ¢ ¢ x + 5y = 2<br />

<br />

<br />

£¢<br />

(x, y, z) ∈ P ⇐⇒ (x, y, z) = (2 − 5y, y, z) = (2, 0, 0) + (−5y, y, z)<br />

⇐⇒ (x, y, z) = (2, 0, 0) + y(−5, 1, 0) + z(0, 0, 1)<br />

(x, y, z) = (2, 0, 0) + λ(−5, 1, 0) + µ(0, 0, 1) λ, µ ∈ IR<br />

¢ P<br />

<br />

¡ <br />

¢ ¡<br />

<br />

P 3x − 2y + 4z − 6 = 0<br />

(x, y, z) ∈ P ⇐⇒ (x, y, z) = 2 4 y − z + 2, y, z<br />

3 3<br />

⇐⇒ (x, y, z) = (2, 0, 0) + 2 4 y − z, y, z<br />

3 3<br />

£¢<br />

⇐⇒ (x, y, z) = (2, 0, 0) + y 2<br />

3 , 1, 0 + z − 4,<br />

0, 1<br />

3

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