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140 CAPÍTULO 13. £ £ ¥ § § ¤§ ¢¢¡ ¤§<br />

¨¥ ¨ (x, y, z) ∈ R1 <br />

y = βx − β<br />

£¢<br />

<br />

<br />

z = −2x + 4<br />

(x, y, z) = (x, βx − β, −2x + 4) = (0, −β, 4) + x(1, β, −2)<br />

¡ <br />

(x, y, z) ∈ R2 <br />

R1 = (0, −β, 4) + 〈(1, β, −2)〉<br />

y = x − 1<br />

£¢<br />

<br />

<br />

<br />

z = −2x + 2 + β<br />

(x, y, z) = (x, x − 1, −2x + 2 + β) = (0, −1, 2 + β) + x(1, 1, −2)<br />

R2 = (0, −1, 2 + β) + 〈(1, 1, −2)〉<br />

¢ ¡ ¥¤ <br />

<br />

<br />

(x, y, £¢ z) (x, y, ¢ £¢ <br />

z)<br />

⎧⎪ ⎨<br />

⎪⎩<br />

y = βx − β<br />

z = −2x + 4<br />

y = x − 1<br />

z = −2x + 2 + β<br />

£¢ ¢ ¢ <br />

<br />

¢ β = 2 ¢ ¡ <br />

<br />

(x, y, z) = (1, 0,<br />

<br />

2)<br />

£¢ d(R1, R2) = 0<br />

<br />

<br />

β 2 ¡ = R1<br />

¢ ¢<br />

<br />

¢£¢ ¨ <br />

<br />

<br />

(1, β, −2) (1, 1, ¢ <br />

−2)<br />

R2 ¢ <br />

R1<br />

¢ ¤<br />

<br />

<br />

<br />

β = 1<br />

<br />

R2<br />

A = (0, −β, 4) =

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