(0 )2 1436587@9BAC9EDGF4HI 7P5QHRFTSVU0DXW6F4H

(0, −1, 4) R1 ∈ B = (0, −1, β + 2) = (0, −1, 4) ∈ R2 v = (1, −2)
R2
1,
d (R1, R2) = u×−→ AB
u
(1,1,−2)×(0,0,1)
= √
6
= (1,−1,0)
√ 6
= √ 2
√6 = 1 √ 3
β 1 = β 2 £¢
=
¢ ¢ ¢¨
R1
A = (0, −β, R1 4) ∈ B = (0, −1, β + R2 2) ∈ u = (1, β, −2)
v = −2) (1, R2
1, R1
R2
AB
u×v
d (R1, R2) = u×v|−→
= |(2−β)(1−β)|
√ 5|1−β|
(−2β+2,0,1−β)|(0,1−β,2−β)
= (−2β+2,0,1−β)
= |2−β|
√ 5
¡ ¨ R A = (3, 1, 2)
¢
(1, 0) 1, ¢ ¢ P 2x + y − z + 9 = 0
¢ R
P
¢ ′ P
P
P = (4, 3, 3)
¢ ′ R R
141
¡ R
P A
¨¥ ¨ R A = (3, 1, 2)
u = (1, 1, 0) P ¢ ¢ 2x + y − z + 9 = 0
¢
v = (2, 1, −1)
¡ P u =
(1, 1, 0) ¡ R
sin (P, R) = |u|v|
uv
= |3|
√ 2 √ 6 = √ 3
2
= sin π
3
π (P, R) =
3
R = A + 〈u〉 ′ P ¡ ¡ R
P = 3)£¢
(4, 3,
P ′
= A + u, −→
AP = (3, 1, 2) + 〈 (1, 1, 0), (1, 2, 1) 〉
′ P
¡
w = (1, 1, 0) × (1, 2, 1) = (1, −1, 1)