(0 )2 1436587@9BAC9EDGF4HI 7P5QHRFTSVU0DXW6F4H

¢ [A | B]
¢
[A | B] =
−−−−→
ℓ2 − ℓ1
−−−−→
1
3 ℓ3
−−−−→
ℓ1 − ℓ3
1 1 1 | a
1 2 3 | b
1 3 2 | c
1 1 1 | a
0 1 2 | b − a
0 2 1 | c − a
1 1 1 | a
⎡
⎢
⎣
0 1 2 | b − a
0 0 1 |
1 1 0 |
0 1 0 |
0 0 1 |
−−−−→
ℓ3 − ℓ1
2b−a−c
3
−−−−−→
2ℓ2 − ℓ3
4a−2b+c
3
2c−b−a
3
2b−a−c
3
1 1 1 | a
1 2 3 | b
0 2 1 | c − a
−−−−−→
ℓ2 − 2ℓ3
⎤
⎥
⎦ −−−−→
ℓ1 − ℓ2
1 1 1 | a
0 1 2 | b − a
0 0 3 | 2b − a − c
1 1 1 | a
0 1 0 |
0 0 1 |
1 0 0 |
0 1 0 |
0 0 1 |
2c−b−a
3
2b−a−c
3
5a−b−c
3
2c−b−a
3
2b−a−c
3
r(A) = r ([A | B]) = 3 ¡ ¢
¡
⎡ ⎤
⎣
x
y
z
⎦ =
⎡
⎢
⎣
5a−b−c
3
5a−b−c
3
5a−b−c
M3×1(IR) ¡ ¢
1
1
a
b
c
⇐⇒
⇐⇒
a
b
c
a
b
c
a
b
c
1
1
,
1
2
3
3
⎤
⎥
⎦
3
2
M3×1(IR)¥¤ ¡ α
∈ β γ
=
=
1
= α 1
1
α
α
α
+
+ β
β
2β
3β
α + β + γ
α + 2β + 3γ
α + 3β + 2γ
1
2
3
+
+ γ
γ
3γ
2γ
¢
(α, β, γ) = ¡ ¨
5a−b−c
3
a
b
c
, 5a−b−c,
3
5a−b−c
3
= 5a−b−c
3
1
1
1
+ 5a−b−c
3
1
2
3
1
3
2
+ 5a−b−c
3
1
3
2
89