(0 )2 1436587@9BAC9EDGF4HI 7P5QHRFTSVU0DXW6F4H
(0 )2 1436587@9BAC9EDGF4HI 7P5QHRFTSVU0DXW6F4H
(0 )2 1436587@9BAC9EDGF4HI 7P5QHRFTSVU0DXW6F4H
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
148 CAPÍTULO 14. ¦£¦£ ££<br />
<br />
¢<br />
§ £ ¡ ¢ ¤£¦¥ § ¢ ©¨<br />
α = 0 β = 1 <br />
<br />
¡ ¨ A n α ∈ IR \ {0}<br />
<br />
<br />
A (αA) = α n−1 det A In<br />
¨¥ ¨ § ¤£ ¡ 1 <br />
<br />
<br />
<br />
<br />
<br />
<br />
a + b a a<br />
a a + b a<br />
a a a + b<br />
<br />
<br />
<br />
= (a + b) <br />
<br />
a + b a<br />
a a + b<br />
<br />
<br />
− a <br />
a a<br />
a a + b<br />
<br />
<br />
+ a <br />
= (a + b) ((a + b) 2 − a 2 ) − a (a(a + b) − a 2 ) + a (a 2 − a(a + b))<br />
= (a + b) (b 2 + 2ab) − 2a (ab) = 3ab 2 + b 3 = b 2 (3a + b)<br />
a a + b<br />
a a<br />
1 2 3 a c <br />
b<br />
<br />
<br />
<br />
abc <br />
<br />
a 1 bc<br />
b 1 ac<br />
c 1 ab<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
= bc <br />
<br />
<br />
<br />
<br />
= abc <br />
<br />
a 2 a abc<br />
b 1 ac<br />
c 1 ab<br />
a 2 a 1<br />
b 2 b 1<br />
c 2 c 1<br />
abc = 0 <br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
a 1 bc<br />
b 1 ac<br />
c 1 ab<br />
<br />
<br />
<br />
<br />
<br />
= abc<br />
abc<br />
<br />
<br />
<br />
<br />
<br />
<br />
= (1 − λ) <br />
λ ∈ IR <br />
det(A − λI3) =<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
= c <br />
<br />
<br />
<br />
<br />
<br />
<br />
a 2 a 1<br />
b 2 b 1<br />
c 2 c 1<br />
1 − λ 0 −1<br />
1 2 − λ 1<br />
2 2 3 − λ<br />
<br />
<br />
<br />
<br />
2 − λ 1<br />
2 3 − λ<br />
a 2 a abc<br />
b 2 b bac<br />
c 1 ab<br />
<br />
<br />
<br />
<br />
=<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
−<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
=<br />
<br />
<br />
<br />
<br />
<br />
a 2 a 1<br />
b 2 b 1<br />
c 2 c 1<br />
1 2 − λ<br />
2 2<br />
<br />
<br />
<br />
<br />
<br />
a 2 a abc<br />
b 2 b bac<br />
c 2 c cab<br />
= (1 − λ) ((2 − λ)(3 − λ) − 2) − 2 + 2(2 − λ)<br />
= (1 − λ) ((2 − λ)(3 − λ) − 2) + 2(1 − λ)<br />
= (1 − λ)(2 − λ)(3 − λ)