28.05.2014 Views

r - The Hong Kong Polytechnic University

r - The Hong Kong Polytechnic University

r - The Hong Kong Polytechnic University

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Example 3<br />

6<br />

A portal frame is shown in Figure 1. A , A , P are random variables. Modulus of elasticity is E = 2.0 × 10<br />

1 2<br />

KPa. Moments of inertia of beams and columns are I = A 2<br />

/12<br />

1 1 and I 2<br />

= A /6<br />

2 2<br />

. <strong>The</strong> limit state function<br />

is defined as in [20]:<br />

g( x) = 0.01 −u<br />

( x )<br />

3<br />

(20)<br />

Where, u ( x ) is the horizontal displacement of point 3. <strong>The</strong> statistical parameters are shown in Table 4. All the<br />

3<br />

variables are assumed to be uncorrelated.<br />

P<br />

2 A 2 3<br />

A1 A1<br />

4<br />

1 4<br />

4<br />

Figure 1 <strong>The</strong> diagram of the portal frame (unit:m)<br />

Table 4 <strong>The</strong> statistical parameters of variables of example 3<br />

Coefficient of<br />

Variables Uint Mean μ<br />

variation<br />

Distribution Type<br />

A1<br />

m 2 0.36 0.036 Log-normal<br />

A2<br />

m 2 0.18 0.018 Log-normal<br />

P kN 20 5 Extreme-I<br />

<strong>The</strong>re are 3 random variables. In accordance with the distribution, samples were distributed uniformly within<br />

μ − 3 σ, μ + 3σ<br />

. In order to ensure the accuracy of response surface, uniform distribution experimental<br />

[ ]<br />

2<br />

design table ( 30<br />

30 )<br />

U is used to decide 30 tests. <strong>The</strong> failure probability is 2.299×10 -3 and the reliability<br />

index is 2.8339 calculated by UDM-SVM RSM proposed in this paper. <strong>The</strong> failure probability obtained by<br />

Monte-Carlo simulation based on importance sampling using 2000 simulations is 2.3223×10 -3 (Deng et al.<br />

2005) and the reliability index is 2.8307 . It is evident that these results correspond quite well.<br />

Example 4<br />

Figure 2 is a calculation diagram of plane frame structure with three spans and 12 layers. Elasticity Modulus of<br />

7<br />

each element is E = 2.0× 10 Pa . <strong>The</strong> relationship between inertia moment and area of element section<br />

is I = α A i2 ( i = 1,2,3,4,5) . <strong>The</strong> area A<br />

i i i<br />

of element section and external load P are chosen as random<br />

variables. To consider the condition of normal use, the maximum allowable deformation [ U ] is equal to 0.096<br />

according to the requirements of the specification. <strong>The</strong>refore, the limit state function can be expressed as:<br />

G = 0.096 − U ( A, A , A , A , A , P)<br />

(21)<br />

max 1 2 3 4 5<br />

<strong>The</strong> statistical characteristics of variables are shown in tableⅡ.<br />

-404-

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!