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Analisis Rangkaian Rangkaian Listrik - Ee-cafe.org

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13. Carilah fungsi alih dari suatu rangkaian jika diketahui bahwa<br />

tanggapannya terhadap sinyal anak tangga adalah :<br />

−5000<br />

t<br />

a). g(<br />

t)<br />

= −e<br />

u(<br />

t);<br />

b). g(<br />

t)<br />

=<br />

c). g(<br />

t)<br />

=<br />

d). g(<br />

t)<br />

=<br />

e). g(<br />

t)<br />

=<br />

f). g(<br />

t)<br />

=<br />

g). g(<br />

t)<br />

=<br />

−5000<br />

t<br />

( 1−<br />

e ) u(<br />

t);<br />

−5000<br />

t<br />

( −1+<br />

5e<br />

) u(<br />

t);<br />

−1000<br />

t −2000<br />

t<br />

( e − e ) u(<br />

t);<br />

−1000<br />

t −2000<br />

t<br />

( e − e ) u(<br />

t<br />

−1000<br />

t<br />

( e sin 2000t<br />

) u(<br />

t)<br />

−1000<br />

t<br />

( e sin 2000t<br />

)<br />

−<br />

h). h(<br />

t)<br />

= −1000<br />

e<br />

1000 t<br />

−<br />

i). h(<br />

t)<br />

= δ(<br />

t)<br />

− 1000 e<br />

−<br />

j). h(<br />

t)<br />

= δ(<br />

t)<br />

− 2000 e<br />

k). h(<br />

t)<br />

=<br />

l). h(<br />

t)<br />

=<br />

u(<br />

t);<br />

1000 t<br />

1000 t<br />

);<br />

u(<br />

t) ;<br />

u(<br />

t) ;<br />

u(<br />

t)<br />

−1000<br />

t<br />

( e sin 2000t)<br />

u(<br />

t);<br />

−1000<br />

t<br />

( e cos 2000t<br />

) u(<br />

t)<br />

14. Dengan menggunakan integral konvolusi carilah tegangan kapasitor<br />

pada rangkaian seri RC jika tegangan masukannya: (a) v 1 (t) = tu(t) ;<br />

(b) v 1 (t) = A e −α t u(t).<br />

120 Sudaryatno Sudirham, <strong>Analisis</strong> <strong>Rangkaian</strong> <strong>Listrik</strong> (2)

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