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Introduction to Acoustics

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Because any vec<strong>to</strong>r field may be decomposed in<strong>to</strong><br />

a sum of two fields, one with zero curl and the other with<br />

zero divergence, one can set the displacement vec<strong>to</strong>r ξ<br />

<strong>to</strong><br />

ξ =∇Φ +∇× Ψ (3.81)<br />

in terms of a scalar and a vec<strong>to</strong>r potential. This expression<br />

will satisfy (3.77) identically, provided the two<br />

potentials separately satisfy<br />

∇ 2 Φ − 1<br />

c 2 1<br />

∇ 2 Ψ − 1<br />

c 2 2<br />

∂2Φ = 0 , (3.82)<br />

∂t2 ∂2Ψ = 0 . (3.83)<br />

∂t2 Both of these equations are of the form of the simple<br />

wave equation of (3.74). The first corresponds <strong>to</strong> longitudinal<br />

wave propagation, and the second corresponds<br />

<strong>to</strong> shear wave propagation. The quantities c1 and c2 are<br />

referred <strong>to</strong> as the dilatational and shear wave speeds,<br />

respectively.<br />

If the displacement field is irrotational, so that the<br />

curl of the displacement vec<strong>to</strong>r is zero (as is so for sound<br />

in fluids), then each component of the displacement field<br />

satisfies (3.82). If the displacement field is solenoidal,<br />

so that its divergence is zero, then each component of<br />

the displacement satisfies (3.83).<br />

3.3.5 Linearized Equations<br />

for a Viscous Fluid<br />

For the restricted but relatively widely applicable case<br />

when the Navier–S<strong>to</strong>kes–Fourier equations are presumed<br />

<strong>to</strong> hold and the characteristic scales of the<br />

ambient medium and the disturbance are such that<br />

the ambient flow is negligible, and the coefficients are<br />

idealizable as constants, the linear equations have the<br />

form appropriate for a disturbance in a homogeneous,<br />

time-independent, non-moving medium, these equations<br />

being<br />

∂ρ ′<br />

∂t + ρ0∇·v ′ = 0 , (3.84)<br />

∂v<br />

ρ0<br />

′<br />

∂t =−∇p′ � �<br />

1<br />

+ µ + µB ∇<br />

3 � ∇·v ′�<br />

+ µ∇ 2 v ′ , (3.85)<br />

∂s<br />

ρ0T0<br />

′<br />

∂t = κ∇2 T ′ , (3.86)<br />

ρ ′ = 1<br />

c 2 p′ −<br />

� �<br />

ρβT<br />

cp<br />

s<br />

0<br />

′ , (3.87)<br />

Basic Linear <strong>Acoustics</strong> 3.3 Equations of Linear <strong>Acoustics</strong> 37<br />

T ′ � �<br />

Tβ<br />

=<br />

ρcp<br />

0<br />

p ′ � �<br />

T<br />

+ s<br />

cp 0<br />

′ . (3.88)<br />

The primes on the perturbation field variables are needed<br />

here <strong>to</strong> distinguish them from the corresponding ambient<br />

quantities.<br />

3.3.6 Acoustic, Entropy,<br />

and Vorticity Modes<br />

In general, any solution of the linearized equations<br />

for a fluid with viscosity and thermal conductivity<br />

can be regarded [3.30, 32–34] asasumofthreebasic<br />

types of solutions. The common terminology for<br />

these is: (i) the acoustic mode, (ii) the entropy mode,<br />

and (iii) the vorticity mode. Thus, with appropriate<br />

subscripts denoting the various fundamental mode<br />

types, one writes the fluid velocity perturbation in the<br />

form,<br />

v ′ = vac + vent + vvor , (3.89)<br />

with similar decompositions for the other field variables.<br />

The decomposition is intended <strong>to</strong> be such that, for waves<br />

of constant frequency, each field variable’s contribution<br />

from any given mode satisfies a partial differential equation<br />

that is second order [rather than of some higher<br />

order as might be derived from (3.84)–(3.88)] in the<br />

spatial derivatives. That such a decomposition is possible<br />

follows from a theorem [3.35, 36] that any solution<br />

of a partial differential equation of, for example, the<br />

form,<br />

� �� �� � 2 2 2<br />

∇ + λ1 ∇ + λ2 ∇ + λ3 ψ = 0 , (3.90)<br />

can be written as a sum,<br />

ψ = ψ1 + ψ2 + ψ3 , (3.91)<br />

where the individual terms each satisfy second-order<br />

differential equations of the form,<br />

� � 2<br />

∇ + λi ψi = 0 . (3.92)<br />

This decomposition is possible providing no two of<br />

the λi are equal. [In regard <strong>to</strong> (3.90), one should<br />

note that each of the three opera<strong>to</strong>r fac<strong>to</strong>rs is<br />

a second-order differential opera<strong>to</strong>r, so the overall<br />

equation is a sixth-order partial differential equation.<br />

One significance of the theorem is that one<br />

has replaced the seemingly formidable problem of<br />

solving a sixth-order partial differential equation by<br />

that of solving three second-order partial differential<br />

equations.]<br />

Part A 3.3

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