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10. Appendix

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Solution to Problem 9.14 671<br />

Note that in obtaining this plot we have assumed that the electron effective<br />

masses in the well (m1) and in the barrier (m2) are equal, respectively, to<br />

0.037 and 0.0023 times the free electron mass.<br />

Electron Energy (eV)<br />

Transmission curve obtained for m1=0.037mo and m2=0.0023mo.<br />

To calculate the transmission coefficient under applied bias one has to tilt the<br />

barrier and the well and approximate the tilted potential with piece-wise constant<br />

potentials. With slight variation in the computer program this computation<br />

can be done easily and is left as an exercise for the students. The students<br />

are also urged to vary the effective masses and other parameters to see their<br />

effects on the transmission curve.

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