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10. Appendix

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626 <strong>Appendix</strong> B<br />

As an example, we will calculate the probability for the scattering process<br />

in which the electron absorbs a phonon. In this case the electron-phonon matrix<br />

element is given by (under the simplifying assumption that eq is parallel<br />

to q):<br />

<br />

〈k, Nq|HeLA|k ′ , Nq 1〉 2 <br />

<br />

2 <br />

(ac) (q · eq) 2<br />

<br />

<br />

〈k, Nq|C q exp[i(q · r ˆt)]k′ <br />

<br />

, Nq 1〉<br />

(ac)<br />

q<br />

<br />

2<br />

q<br />

2NVρˆ<br />

<br />

2NVρˆ<br />

<br />

(q) 2 Nq‰(Ek Ek ′ Eq)‰(k k ′ q)<br />

In obtaining the above expression we have used the result that the probability<br />

of absorbing a phonon is proportional to Nq. Substituting this matrix element<br />

into the Fermi Golden Rule we obtain the total scattering rate of the electron<br />

out of the state k via absorption of phonon:<br />

<br />

2apple <br />

2<br />

P(k) (ac)<br />

<br />

k ′ <br />

<br />

2NVρˆ<br />

,q<br />

<br />

2apple<br />

(ac)<br />

<br />

2<br />

<br />

<br />

2NVρ<br />

q<br />

<br />

(q) 2 Nq‰(Ek Ek ′ Eq)‰(k k ′ q)<br />

<br />

q<br />

2 Nq‰(Ek Ekq Eq)<br />

ˆ<br />

It should be noted that the LA phonon frequency ˆ vsq where vs is the<br />

LA phonon velocity and therefore cannot be taken outside the summation<br />

over q in the above expression. Notice that P(k) is essentially the same as<br />

(5.41). In the high temperature limit, where kBT ≫ ˆ and Nq ≫ 1, we can<br />

approximate Nq ∼ kBT/(vsq) so that the q 2 term inside the summation sign<br />

is cancelled by the Nq/ˆ term. The final result can be reduced to:<br />

P(k) ∼ ‰(Ek Ekq Eq)<br />

except for a constant of proportionality which depends on material properties,<br />

such as the density, sound velocity, and the deformation potential. The<br />

way to calculate the allowed values of q is shown geometrically in Fig. 5.1(a).<br />

The summation over q can be converted into an integral over q as shown in<br />

(5.42a). The resultant expression is:<br />

P(k) <br />

<br />

a 2 c kBT<br />

8apple 2 ρv 2 s<br />

<br />

2appleq 2 dq d cos £‰<br />

<br />

2 q<br />

2m ∗<br />

<br />

(q 2k cos £) v2q<br />

After integration over cos £ and q the final expression becomes:<br />

<br />

a<br />

P(k) <br />

2 <br />

∗<br />

ckBTm q2 <br />

max<br />

2k<br />

4appleρ 3 v 2 s<br />

where qmax represents the maximum value of the wave vector of the phonon<br />

absorbed. We will now make the approximation that qmax ∼ 2k as in 5.2.4.<br />

With this simplification the probability of absorbing a phonon is given by:<br />

<br />

a<br />

P(k) <br />

2 √<br />

∗<br />

2<br />

ckBTm 2ackBT(m k <br />

∗ ) 3/2<br />

<br />

E 1/2<br />

2appleρ 3 v 2 s<br />

2appleρ 4 v 2 s<br />

2

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