10. Appendix
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626 <strong>Appendix</strong> B<br />
As an example, we will calculate the probability for the scattering process<br />
in which the electron absorbs a phonon. In this case the electron-phonon matrix<br />
element is given by (under the simplifying assumption that eq is parallel<br />
to q):<br />
<br />
〈k, Nq|HeLA|k ′ , Nq 1〉 2 <br />
<br />
2 <br />
(ac) (q · eq) 2<br />
<br />
<br />
〈k, Nq|C q exp[i(q · r ˆt)]k′ <br />
<br />
, Nq 1〉<br />
(ac)<br />
q<br />
<br />
2<br />
q<br />
2NVρˆ<br />
<br />
2NVρˆ<br />
<br />
(q) 2 Nq‰(Ek Ek ′ Eq)‰(k k ′ q)<br />
In obtaining the above expression we have used the result that the probability<br />
of absorbing a phonon is proportional to Nq. Substituting this matrix element<br />
into the Fermi Golden Rule we obtain the total scattering rate of the electron<br />
out of the state k via absorption of phonon:<br />
<br />
2apple <br />
2<br />
P(k) (ac)<br />
<br />
k ′ <br />
<br />
2NVρˆ<br />
,q<br />
<br />
2apple<br />
(ac)<br />
<br />
2<br />
<br />
<br />
2NVρ<br />
q<br />
<br />
(q) 2 Nq‰(Ek Ek ′ Eq)‰(k k ′ q)<br />
<br />
q<br />
2 Nq‰(Ek Ekq Eq)<br />
ˆ<br />
It should be noted that the LA phonon frequency ˆ vsq where vs is the<br />
LA phonon velocity and therefore cannot be taken outside the summation<br />
over q in the above expression. Notice that P(k) is essentially the same as<br />
(5.41). In the high temperature limit, where kBT ≫ ˆ and Nq ≫ 1, we can<br />
approximate Nq ∼ kBT/(vsq) so that the q 2 term inside the summation sign<br />
is cancelled by the Nq/ˆ term. The final result can be reduced to:<br />
P(k) ∼ ‰(Ek Ekq Eq)<br />
except for a constant of proportionality which depends on material properties,<br />
such as the density, sound velocity, and the deformation potential. The<br />
way to calculate the allowed values of q is shown geometrically in Fig. 5.1(a).<br />
The summation over q can be converted into an integral over q as shown in<br />
(5.42a). The resultant expression is:<br />
P(k) <br />
<br />
a 2 c kBT<br />
8apple 2 ρv 2 s<br />
<br />
2appleq 2 dq d cos £‰<br />
<br />
2 q<br />
2m ∗<br />
<br />
(q 2k cos £) v2q<br />
After integration over cos £ and q the final expression becomes:<br />
<br />
a<br />
P(k) <br />
2 <br />
∗<br />
ckBTm q2 <br />
max<br />
2k<br />
4appleρ 3 v 2 s<br />
where qmax represents the maximum value of the wave vector of the phonon<br />
absorbed. We will now make the approximation that qmax ∼ 2k as in 5.2.4.<br />
With this simplification the probability of absorbing a phonon is given by:<br />
<br />
a<br />
P(k) <br />
2 √<br />
∗<br />
2<br />
ckBTm 2ackBT(m k <br />
∗ ) 3/2<br />
<br />
E 1/2<br />
2appleρ 3 v 2 s<br />
2appleρ 4 v 2 s<br />
2