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10. Appendix

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620 <strong>Appendix</strong> B<br />

two-dimensional and a possible set of basis function has the form: x 2 y 2 and<br />

z 2 [x 2 y 2 ]/2. In this case y 2 and z 2 will not change sign under C2(x) rotation.<br />

To achieve the result with the Si wave functions we find that [Y Y] and<br />

[ZZ] will not change sign under the C2(x) rotation. Thus the normalized linear<br />

combination for the E irreducible representations are: {[XX][YY]}/2<br />

and {[2Z 2Z] [X X] [Y Y]}/ √ 12.<br />

Solution to Problem 4.5<br />

Assume that the imaginary part of an analytic function F(E) is given by:<br />

Im[F(E)] [(E E ′ ) 2 ° 2 ] 1 . (4.5a)<br />

Applying the Kramers-Kronig relation (4.56), we find that the real part of<br />

F(E) is given by:<br />

Re[f (E)] 1<br />

apple P<br />

1<br />

apple P<br />

∞<br />

∞ ∞<br />

∞<br />

Im[F(z)]<br />

z E dz<br />

(1)<br />

(z E)[(z E ′ ) 2 ° 2 ] dz<br />

(4.5b)<br />

One way to calculate this definite integral is to rewrite the integrand as a sum:<br />

1/(z E)[(z E ′ ) 2 ° 2 ] [A/(z E)] [B/(z E ′ i°)]<br />

[C/(z E ′ i°)]<br />

(4.5c)<br />

where i2 (1), A 1/[(E E ′ )2 ° 2 ], B (i/2°)[1/(E E ′ i°)]<br />

and C (i/2°)[1/(E E ′ i°)]. For each term in (4.5c) the corresponding<br />

integration in (4.5b) can be performed with the help of a contour integral. As<br />

an example, let us consider:<br />

∞<br />

dz<br />

P<br />

∞ z (E ′ (4.5d)<br />

i°)<br />

First, we will simplify the integral with a change in variable: x z E ′ so that<br />

(4.5d) becomes:<br />

∞<br />

dx<br />

P<br />

(4.5e)<br />

∞ x i°<br />

The integrand in (4.5e) has a pole at x i°. To obtain its principal value we<br />

consider an integral over a closed contour C in the complex z ′ -plane where<br />

z ′ x iy:

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