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10. Appendix

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Therefore the result of I ′ on „B is to change it to:<br />

(1/ √ 2)[exp(i3apple/4))|S2〉 exp(iapple/4) exp(i3apple/4)|S1〉]<br />

(1/ √ 2)[ exp(iapple/4))|S2〉 exp(apple)|S1〉]<br />

(1/ √ 2)[exp(iapple/4))|S2〉 |S1〉]<br />

Solution to Problem 2.20 599<br />

„B.<br />

Thus we find the lower energy bonding s-orbital to have odd parity under I ′ .<br />

Again the energy separating the bonding and anti-bonding s-orbitals in Si is<br />

only 2|Vss| 8.13 eV only. But the agreement with the full scale pseudopotential<br />

calculation is better than the result in (a).<br />

(c) One may ask then: what will the electron density look like for the odd<br />

parity (bonding) orbital when k is at the L point? Will this electron density<br />

have a maximum between the two atoms as we would expect for the bonding<br />

state? The answer is yes. To understand why the bonding electronic wave<br />

function has odd parity while the anti-bonding electronic wave function has<br />

even parity we will examine the parity of the zone-center acoustic and optical<br />

phonons in the diamond lattice. In Fig. 2.7 we have shown schematically<br />

the displacement vectors for both phonon modes. We notice that the displacement<br />

vectors point in the same direction for both atoms within the unit cell<br />

in the case of the acoustic phonon. Clearly, if we extrapolate the atomic displacement<br />

to the midpoint between the two atoms it will not be zero. In a<br />

sense the acoustic phonon is the analogue of a bonding electronic state and<br />

yet the acoustic phonon has odd parity under the operation I ′ . On the other<br />

hand, the displacement vectors for the optical phonon point in opposite directions<br />

at the two atoms inside the unit cell. When extrapolated to the midpoint<br />

of the two atoms in the unit cell we expect the phonon wave function should<br />

vanish as in an anti-bonding state but its parity is even under the operation<br />

I ′ . The reason why the parity of these phonon modes seems to be opposite to<br />

what one may expect intuitively lies in the translation by T of the lattice under<br />

the operation I ′ . This translation causes the parity of the phonon modes<br />

to change sign. Without this translation the acoustic phonon parity would indeed<br />

be even while the parity of the optical phonon would be odd. The same<br />

is true for the electron wave functions when k is at the L point. The translation<br />

operation T introduces a phase factor: exp[ik · T] to the electronic wave<br />

functions. When k (apple/a)(1, 1, 1) at the L point, this phase vector is equal to<br />

exp(i3apple/4) and causes the parity of the electron wave function to reverse sign<br />

as shown in (b). Thus the operation T causes both the phonon wave functions<br />

at k 0 and the electronic wave functions for k (apple/a)(1, 1, 1) to reverse<br />

the sign of their parity. This phase factor does not cause a problem when one<br />

consider the “compatibility” between the zone-center and L point electronic<br />

wave functions since this phase factor is zero when k (0, 0, 0). If we start at<br />

k 0 we find that the parity of the bonding state (where the electron density<br />

is non-zero at the mid-point between the two atoms in the unit cell) is even.<br />

The parity of the electronic wave function changes sign as k approaches the L<br />

point but the state remains a bonding state.

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