10. Appendix
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Therefore the result of I ′ on „B is to change it to:<br />
(1/ √ 2)[exp(i3apple/4))|S2〉 exp(iapple/4) exp(i3apple/4)|S1〉]<br />
(1/ √ 2)[ exp(iapple/4))|S2〉 exp(apple)|S1〉]<br />
(1/ √ 2)[exp(iapple/4))|S2〉 |S1〉]<br />
Solution to Problem 2.20 599<br />
„B.<br />
Thus we find the lower energy bonding s-orbital to have odd parity under I ′ .<br />
Again the energy separating the bonding and anti-bonding s-orbitals in Si is<br />
only 2|Vss| 8.13 eV only. But the agreement with the full scale pseudopotential<br />
calculation is better than the result in (a).<br />
(c) One may ask then: what will the electron density look like for the odd<br />
parity (bonding) orbital when k is at the L point? Will this electron density<br />
have a maximum between the two atoms as we would expect for the bonding<br />
state? The answer is yes. To understand why the bonding electronic wave<br />
function has odd parity while the anti-bonding electronic wave function has<br />
even parity we will examine the parity of the zone-center acoustic and optical<br />
phonons in the diamond lattice. In Fig. 2.7 we have shown schematically<br />
the displacement vectors for both phonon modes. We notice that the displacement<br />
vectors point in the same direction for both atoms within the unit cell<br />
in the case of the acoustic phonon. Clearly, if we extrapolate the atomic displacement<br />
to the midpoint between the two atoms it will not be zero. In a<br />
sense the acoustic phonon is the analogue of a bonding electronic state and<br />
yet the acoustic phonon has odd parity under the operation I ′ . On the other<br />
hand, the displacement vectors for the optical phonon point in opposite directions<br />
at the two atoms inside the unit cell. When extrapolated to the midpoint<br />
of the two atoms in the unit cell we expect the phonon wave function should<br />
vanish as in an anti-bonding state but its parity is even under the operation<br />
I ′ . The reason why the parity of these phonon modes seems to be opposite to<br />
what one may expect intuitively lies in the translation by T of the lattice under<br />
the operation I ′ . This translation causes the parity of the phonon modes<br />
to change sign. Without this translation the acoustic phonon parity would indeed<br />
be even while the parity of the optical phonon would be odd. The same<br />
is true for the electron wave functions when k is at the L point. The translation<br />
operation T introduces a phase factor: exp[ik · T] to the electronic wave<br />
functions. When k (apple/a)(1, 1, 1) at the L point, this phase vector is equal to<br />
exp(i3apple/4) and causes the parity of the electron wave function to reverse sign<br />
as shown in (b). Thus the operation T causes both the phonon wave functions<br />
at k 0 and the electronic wave functions for k (apple/a)(1, 1, 1) to reverse<br />
the sign of their parity. This phase factor does not cause a problem when one<br />
consider the “compatibility” between the zone-center and L point electronic<br />
wave functions since this phase factor is zero when k (0, 0, 0). If we start at<br />
k 0 we find that the parity of the bonding state (where the electron density<br />
is non-zero at the mid-point between the two atoms in the unit cell) is even.<br />
The parity of the electronic wave function changes sign as k approaches the L<br />
point but the state remains a bonding state.